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Dominik [7]
3 years ago
14

The price of 3.4 pounds of apples at $.60 per pound is how much money?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
4 0
Hey there Olivia0,

The price of 3.4 pounds of apples is $0.60 per pound. How much is the total?

Answer:

1 pound = $0.60
3.4 pounds = $0.60 x 3.4
                   = $2.04

Hope this helps :D

<em>~Top♥</em>
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Who is correct? Thanks for the help
Aleksandr-060686 [28]
I believe Hector is correct

Explanation: for every 1 hour the income is $10, therefore working 32 hours will give you $320 as Hector stated, while working 18 hours will not give you $160 as Hannah stated, it will give you $180
4 0
2 years ago
Solve the inequality. Graph the solutions. h – 2 &lt; –1
solniwko [45]
H < 1 I think that's the answer
8 0
3 years ago
A student earned grades of​ B, B,​ A, C, and D. Those courses had these corresponding numbers of credit​ hours: 4,​ 5, 1,​ 5, 4.
antiseptic1488 [7]

Answer:

<h2> 1.69</h2>

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

5 0
3 years ago
Express the following as a single discount rate.
yuradex [85]

Answer:

<em>37% </em>

<em>46.8% </em>

<em>65.8% </em>

<em>59.68% </em>

<em>41.8% </em>

<em>52.5%</em>

Step-by-step explanation:

<u>Discount Rates </u>

It's a way to express that a quantity will be reduced to some other by a fixed percentage. For example, taking 40% off a $50 price means:

* Operating 40*50/100=$20 This is the discount

* Subtracting from the original price: $50 - $20 = $30. This is the reduced quantity.

The trick is doing all of that procedure more efficiently to solve the question. At the end of the procedure we did this

50 - 40*50/100 = 50*(1 - 40/100) = 50*(1-0.4)= 50 * 0.6 = $30

This means we get the same result by only multipying by a factor which is one minus the discount percentage divided by 100.

Let's start with the first homework

Discount 25% and 16%. The first discount is made by multiplying by 0.75 and the second my multiplying by 0.84. This means that the total discounted value is

0.75*0.84 = 0.63. That is a single discount of 1-0.63 = 37%

Discount 30%, 20%, and 5%. The product is

0.70 * 0.80 * 0.95 = 0.532, a single discount of 1-0.532 = 46.8%

Discount 60%, 10%, and 5%

0.40 * 0.90 * 0.95 = 0.342, a single discount of 65.8%

Discount 40%, 20%, 12 1/2%, and 4%. Let's recall that 12 1/2% = 12.5%. The product is

0.60 * 0.80 * 0.875 * 0.96 = 0.4032. A single discount or 1-0.4032 = 59.68%

Discount 25%, 20%, and 3%

0.75 * 0.80 * 0.97 = 0.582. Single discount of 41.8%

Discount 331/3%, 25%, and 5%

0.66 * 0.75 * 0.95 = 0.475, single discount of 52.5%

6 0
3 years ago
If the point (a, b) is equidistant from the points (-a, 2) and (2, -b), then prove that 3(a+b)+4=0​
erastova [34]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Since (a, b) is equidistant from (-a, 2) and (2, -b), then it is the midpoint of the those two points. Use Midpoint formula to find (a, b).

M_x=\dfrac{x_1+x_2}{2}\qquad \qquad \qquad M_y=\dfrac{y_1+y_2}{2}\\\\\\a=\dfrac{-a+2}{2}\qquad \qquad \qquad \quad b=\dfrac{2-b}{2}\\\\\\2a=-a+2\qquad \qquad \qquad \quad 2b=2-b\\\\\\3a=2\qquad \qquad \qquad \qquad \qquad 3b=2\\\\\\a=\dfrac{2}{3}\qquad \qquad \qquad \qquad \qquad b=\dfrac{2}{3}

3(a + b) - 4 = 0

3\bigg(\dfrac{2}{3}+\dfrac{2}{3}\bigg)-4=0\\\\\\3\bigg(\dfrac{4}{3}\bigg)-4=0\\\\\\4-4=0\\\\0=0\qquad \text{TRUE!}

<em>Notice that I changed the equation to "negative 4" because the equation you provided did not make a true statement.</em>

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4 0
3 years ago
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