Answer: The results agree with the law of conservation of mass
Explanation:
The law of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. On the reactant side, the total mass of reactants is 14.3g and the total product masses is also 14.3g. That implies that no mass was !most in the reaction. The sum of masses on the left hand side corresponds with sum of masses on the right hand side of the reaction equation.
Answer:
kinetic energy
Explanation:
A baseball flying through the air has kinetic energy because of its motion
Answer:
0.86 moles H₂O
Explanation:
To solve this problem, it is important to first determine the balanced chemical equation. The balanced equation is necessary as it will provide the mole-to-mole ratio needed to convert between moles O₂ and moles H₂O.
The unbalanced equation:
C₈H₁₈ (l) + O₂ (g) ---> CO₂ (g) + H₂O (g)
<u>Reactants:</u> 8 carbon, 18 hydrogen, 2 oxygen
<u>Products:</u> 1 carbon, 2 hydrogen, 3 oxygen
As you can see, the equation is not balanced because there are unequal amounts of each element on both sides. Balancing the equation is a matter of guessing-and-checking to see which combination of coefficients work.
The balanced equation:
2 C₈H₁₈ (l) + 25 O₂ (g) ---> 16 CO₂ (g) + 18 H₂O (g)
<u>Reactants:</u> 16 carbon, 36 hydrogen, 50 oxygen
<u>Products:</u> 16 carbon, 36 hydrogen, 50 oxygen
Now that the equation is balanced, we can use the coefficients of O₂ and H₂O to construct our mole-to-mole ratio and perform our conversion. The final answer should have 2 sig figs to match the given value (1.2 moles). The state of matter is most likely not necessary to include in your final answer.
1.2 moles O₂ 18 moles H₂O
--------------------- x ----------------------- = 0.86 moles H₂O
25 moles O₂
1 molecule of NH3 has 3 atoms of H.
6.90*10²⁴ molecules NH3 have 3*6.90*10²⁴ =20.7*10²⁴ atoms H=2.07*10²⁵ atoms H
1 molecule H2O of has 2 atoms of H.
2.60*10²⁵ molecules of H2O have 2*2.60*10²⁵ =5.20 *10²⁵ atoms of H
2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.
