1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sav [38]
3 years ago
12

For the reaction H2PO4- HAsO4 2-HPO4 2-+H2AsO4- what species are a conjugate acid-base pair?

Chemistry
2 answers:
aleksklad [387]3 years ago
8 0

Ionic equation:

\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}

The acid and base in a conjugate pair differ by only one proton \text{H}^{+}. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

\text{H}_2\text{PO}_4^{-} loses one proton to produce \text{HPO}_4^{2-} in this reaction.

\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}

Meanwhile, \text{HAsO}_4^{2-} gains one proton to form \text{H}_2\text{AsO}_4^{-}.

\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}

Therefore

  • \text{H}_2\text{PO}_4^{-} is the conjugate acid  \text{HPO}_4^{2-}, its conjugate base.
  • \text{HAsO}_4^{2-} is the conjugate base of \text{H}_2\text{AsO}_4^{-}, its conjugate acid.
kondaur [170]3 years ago
7 0

Ionic equation:




The acid and base in a conjugate pair differ by only one proton . The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.


loses one proton to produce  in this reaction.




Meanwhile,  gains one proton to form .




Therefore


  • is the conjugate acid  , its conjugate base.
  • is the conjugate base of , its conjugate acid.


You might be interested in
A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How
Irina-Kira [14]
<h3>Answer:</h3>

0.10 L

<h3>Explanation:</h3>

The concentration of glucose  is given as 180 g/L

The mass of glucose is 18 g

  • Concentration in g/L is calculated by dividing mass of the solute by the volume of the solution.
  • When calculating molarity on the other hand, we divide number of moles of the solute by the volume  of the solution.
  • Concentration in g/L = Mass of solute ÷ Volume

Rearranging the formula,

Volume = Mass of the solute ÷ concentration

             = 18 g ÷ 180 g/L

            = 0.10 L

Therefore, volume of water is 0.10 L

6 0
3 years ago
What happens when lead nitrate and potassium iodide are mixed?
lisov135 [29]

Answer:

Explanation: A yellow precipitate o lead iodide is formed. see equation of reaction below: 2KI + Pb(NO3)2 → PbI2 + 2K(NO3)2

Th PbI2 is the insoluble yellow precipitate

7 0
3 years ago
Pls help 2-3 tyvm ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎ ‏‏‎ ‎
Triss [41]

Answer:

I could I guess?

But like only 1 lol

Explanation:

6 0
3 years ago
What is the difference between chemical and physical change with respect
kozerog [31]

Answer:

Physical changes are changes that do not alter the identity of a substance. Chemical changes are changes that occur when one substance is turned into another substance.

Explanation:

5 0
3 years ago
Read 2 more answers
How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos
Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of H_3PO_4 = 54.219 g

Number of atoms of Mg = 7.179\times 10^{23}

Molar mass of H_3PO_4 = 98 g/mol

First we have to calculate the moles of H_3PO_4 and Mg.

\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}

\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol

and,

\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2

From the balanced reaction we conclude that

As, 3 mole of Mg react with 2 mole of H_3PO_4

So, 0.553 moles of Mg react with \frac{2}{3}\times 0.553=0.369 moles of H_3PO_4

From this we conclude that, H_3PO_4 is an excess reagent because the given moles are greater than the required moles and Mg is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of H_2

From the reaction, we conclude that

As, 3 mole of Mg react to give 3 mole of H_2

So, 0.553 mole of Mg react to give 0.553 mole of H_2

Now we have to calculate the volume of H_2  gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies 0.553\times 22.4=12.4L volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0
3 years ago
Other questions:
  • An undiscovered element has three naturally occurring isotopes of X-55, X-57, and X-58. Isotope X-55 has an abundance of 27.80 %
    10·1 answer
  • Which inquiry skill is based on identifying common features?
    12·1 answer
  • what type of bond requires the give and take of electrons? a. ionic b. polar disalent c. polar covalent d. nonpolar covalent
    15·1 answer
  • State evidence from the table indicating that the proportion of the components in a
    15·1 answer
  • Mitochondria _ <br>Plant​
    11·2 answers
  • A gas was at STP. If the pressure increased to 3.5 atm, what would the new<br> temperature be?
    6·1 answer
  • The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol
    5·1 answer
  • Many children are uncomfortable around white lab coats. Specifically explain why this occurs in what a doctor or dentist could d
    14·1 answer
  • What is this and please exactly why :)
    15·2 answers
  • Tear off a small, flat sheet of waxed paper. Use the pipette to dispense a drop of water on the waxed paper. Now, dry the pipett
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!