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devlian [24]
3 years ago
9

What is ΔG for the reaction at body temperature (37.0 °C) if the concentration of A is 1.6 M and the concentration of B is 0.50

M ?
Chemistry
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

The Gibbs free energy is -2997.83 kJ mol-1.

Explanation:

The change in Gibbs free energy of the reaction \Delta G can be calculated using the formula.

\Delta G = -RTlnK

WHere R = Gas constant = 8.314KJ/Kmol

T = the temperature of the reaction in Kelvin = (37.0 + 273) = 310K

K = Raio of molar concentration of the two reactants = 1.6/0.5 = 3.2

Therefore,

\Delta G = -8.314 \times 310 \times  ln (3.2) = -2997.83 kJ mol-1

Therefore the Gibbs free energy is -2997.83 kJ mol-1.

The negative sign indicates that the reaction is spontaneous.

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What changed about the peppered moth population during the second industrial revolution
Marysya12 [62]

Answer:

The months became darker colored and more darker colored moths were sighted.

Explanation:

All of the new air pollution caused the moths to alter there wings and bodies. The moths had no adaptation to this air pollution, causing them to be discolored.

7 0
3 years ago
Read 2 more answers
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
Hydrogen can be extracted from natural gas according to the following equilibrium.
antiseptic1488 [7]

Answer:

2.16x10⁻²

Explanation:

First, let's find out the molar concentrations of the reactants. The molar mass of CH4 is 16 g/mol, and of CO2 is 44 g/mol. The number of moles is the mass divided by the molar mass:

nCH4 = 24.0/16 = 1.5 moles

nCO2 = 88.0/44 = 2 moles

The concentration is the number of moles divded by the volume, thus:

[CH4] = 1.5/1 = 1.50 M

[CO2] = 2/1 = 2.00 M

For the equilibrium reaction, let's do an equilibrium chart:

CH4(g) + CO2(g) ⇄ 2CO(g) + 2H2(g)

1.50 2.00 0 0 Initial

-x -x +2x +2x Reacts (stoichiometry is 1:1:2:2)

1.50-x 2.00-x 2x 2x Equilibrium

As sateted in problem, [CH4] = 2.70*[CO]

1.50 - x = 2.70*2x

1.50 - x = 5.4x

6.4x = 1.50

x = 0.2344

Thus, at equilibrium:

[CH4] = 1.50 - 0.2344 = 1.2656 M

[CO2] = 2.00 - 0.2344 = 1.7656 M

[CO] = 2*0.2344 = 0.4688 M

[H2] = 2*0.2344 = 0.4688 M

The equilibrium constant is the multiplication of the concentrations of the products elevated by their coefficients, divided by the multiplication of the concentration of the reactants elevated by their coefficients.

K = ([CO]²*[H2]²)/([CH4]*[CO2])

K = (0.4688²*0.4688²)/(1.2656*1.7656)

K = 0.0483/2.2345

K = 2.16x10⁻²

7 0
3 years ago
What is the molality of a 13.82% by mass glucose solution? the molar mass of c6h12o6 is 180.16 g/mol?
FrozenT [24]
13.82 g / 180.16 g/mol = .07671 moles
.07671 moles / (86.18 g / 1000 g/kg) = .8901 molal

Let me know if you have any further questions!

5 0
3 years ago
Read 2 more answers
Which of the following is most likely an indication of a chemical change?
mamaluj [8]

Hello there!

Question: Which of the following is most likely an indication of a chemical change?

Answer Choices:

A. A loud sound when an MP3 player is turned on.

B. A loud sound when someone claps their hands.

C. A loud sound when a starter's pistol is fired at a race.

D. A loud sound when a large object falls to the ground.

Correct Answer:

C. A loud sound when a starter's pistol is fired at a race.

Reasons:

A would not be correct since an MP3 player is a mechanical object and does not mix any substances that create a reaction.

B would not be correct since clapping hands causes a loud sound due to two forces slamming together and causes a disturbance in the air.

D would not be correct since a large object falling to the ground does not indicate any chemical reactions or changes since its merely the result of a mass hitting another mass.

C would be correct since the gunpowder mixes with other substances inside the pistol's chamber and causes and explosion, and explosions are part of a chemical reaction indicators.

5 0
3 years ago
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