How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr

Chemistry

1 answer:

JulsSmile [24]3 years ago

3 0

Answer: 403ml

Explanation:

$M=\frac{mol}{L}$

Solve for L;

$L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L$

Convert to mililiters

$0.403L(\frac{1000ml}{1L})=403ml$

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