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andreev551 [17]
3 years ago
5

The change in energy represented by a thermochemical equation is always

Chemistry
1 answer:
Stolb23 [73]3 years ago
4 0
Directionally proportional
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Note - yellow color molecules in pictures are non metal elements
example - co2 , so2,

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What observation would you look for to tell if a reaction was endothermic?
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What is the scientific notation for 5,098.000
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3 0
3 years ago
Read 2 more answers
How many grams of water can be produce from the complete reaction of excess nitric acid and 33.2 mL of 0.245 M lithium hydroxide
Mariulka [41]

Mass of water produced : 0.146 g

<h3>Further explanation</h3>

Given

33.2 mL of 0.245 M lithium hydroxide

Required

mass of water

Solution

Reaction

HNO₃ (aq) + LiOH (aq) → H₂O (l) + LiNO₃ (aq)

mol LiOH :

= M x V

= 0.245 x 33.2 ml

= 8.134 mmol

From the equation, the mol ratio of HNO₃ : H₂O = 1 : 1, so mol H₂O = 8.134 mmol

mass H₂O :

= mol x MW

= 8.134 x 10⁻³ mol x 18 g/mol

= 0.146 g

3 0
2 years ago
For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
Alexxx [7]
<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

6 0
3 years ago
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