Answer:
D) The manager should fail to reject the null hypothesis; there is not enough evidence to conclude that the number of unique daily listeners has changed.
Step-by-step explanation:
The scenario indicates the null hypotheses and alternative hypotheses are
Null hypotheses: The number of unique daily listeners hasn't changed.
Alternative hypotheses: The number of unique daily listeners has changed.
The null hypothesis is rejected if the calculated p-value is less significance level.
We are given that p-value is 0.0743 and confidence level=0.95.
Significance level =α=1-0.95=0.05.
As we can see the p-value is greater than significance level, so, we fail to reject the null hypotheses at 5% significance level.
Thus, we conclude at the 95% confidence level that the manager should fail to reject the null hypothesis; there is not enough evidence to conclude that the number of unique daily listeners has changed
To solve for the confidence interval for the true average
percentage elongation, we use the z statistic. The formula for confidence
interval is given as:
Confidence interval = x ± z σ / sqrt (n)
where,
x = the sample mean = 8.63
σ = sample standard deviation = 0.79
n = number of samples = 56
From the standard distribution tables, the value of z at
95% confidence interval is:
z = 1.96
Therefore substituting the known values into the
equation:
Confidence interval = 8.63 ± (1.96) (0.79) / sqrt (56)
Confidence interval = 8.63 ± 0.207
Confidence interval = 8.42, 8.84
<span> </span>
Answer:
130 papers.
Step-by-step explanation:
1 min per paper therefore 130 mins = 130 papers
:)
Answer:
1) b=-1.6 2) g=3 3) x=0.8 4) w=4.9 5) p=-16.2 6) y=9.2
Step-by-step explanation:
Use inverese operations to isolate variables ex. x+4=2
x times 2 = 6 -4
/2 x=-2
x=3
