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telo118 [61]
3 years ago
12

Imagine tying a string to a ball and twirling it around you. How is this similar to the moon orbiting Earth? In this example, wh

at is providing the constantly changing, inward force?
Physics
1 answer:
leonid [27]3 years ago
5 0
The string kind of acts like gravity 
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What are the opposite ends of a magnet called? A. north and south terminals B. north and south poles C. magnetic fields D. magne
Bezzdna [24]

I think the answer is B.

Hope this helps.

6 0
3 years ago
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A vertically polarized beam of light of intensity 100 W/m2 passes through two ideal polarizers. The transmission axis of the fir
TEA [102]

To solve the problem it is necessary to apply the Malus Law. Malus's law indicates that the intensity of a linearly polarized beam of light, which passes through a perfect analyzer with a vertical optical axis is equivalent to:

I=I_0 cos^2\theta

Where,

I_ {0} indicates the intensity of the light before passing through the polarizer,

I is the resulting intensity, and

\theta indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

Since we have two objects the law would be,

I=I_0cos^2\theta_1*cos^2(\theta_2-\theta_1)

Replacing the values,

I=100*cos^2(20)*cos^2(40-20)

I=100*cos^4(20)

I=77.91W/m^2

Therefore the intesity of the light after it has passes through both polarizers is 77.91W/m^2

7 0
3 years ago
A sound wave travelling in water has a frequency of 100 Hz. The speed of sound in water is 1482 m/s. Calculate the wavelength of
xz_007 [3.2K]
Steps : The formula for wavelength is:
λ = v/f
λ = 1482/100

Answer:

λ = 14.82 m
6 0
2 years ago
QUESTION 7
ryzh [129]

Answer:

<em>The force required is 3,104 N</em>

Explanation:

<u>Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+at

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

\displaystyle a=\frac{0-20.4}{7.4}

a=-2.757\ m/s^2

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F = 1,126\ kg * 2.757\ m/s^2

F= 3,104 N

The force required is 3,104 N

6 0
3 years ago
Which of the following is an example of balanced forces?
Sergio [31]

A seesaw remains stationary when two students of equal weight sit on the ends

c

6 0
3 years ago
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