1.244 m per second the person driving will go
A thermos as another name - it's called the vacuum flask. It's used for<span> storing cryogens when it has certain boiling points that are much lower than the actual room temperature. Many people use thermoses as a cup for drinking, specifically coffee, teas, and other hot drinks.
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Missing part in the text of the problem:
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>
First we can calculate the amount of energy needed to raise the temperature of the water, which is given by

where
m=1.8 g is the mass of the water

is the specific heat capacity of the water

is the increase in temperature.
Substituting the data, we find

We know that each photon carries an energy of

where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:

So, the energy of a single photon of this frequency is

and the number of photons needed is the total energy needed divided by the energy of a single photon:
Answer:
Gay-Lussac’s law, because as the pressure increases, the temperature increases
Explanation:
First of all, we can notice that the volume of the tank is fixed: this means that the volume of the air inside is also fixed.
This means that in this situation we can apply Gay-Lussac's law, which states that:
"for a gas kept at constant volume, the pressure of the gas is proportional to the absolute temperature of the gas".
Mathematically:

where p is the pressure in Pascal and T is the temperature in Kelvin.
In this case, the tank is filled with air: this means that the pressure of the gas inside the tank increases. And therefore, according to Gay-Lussac's law, the temperature will increase proportionally, and this explains why the tank gets hot.