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2 years ago

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In this lab, you observed how different factors such as velocity, gradient, and ____ , or amount of water in a stream, affect th

e rate of ___, the transport of materials from one area to another by water.

2 answers:

Elina [12.6K]2 years ago

8 0

Answer:

volume and erosion

Explanation:

egoroff_w [7]2 years ago

7 0

Answer:

volume and erosion

Explanation:

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Convert 5.7 cm to mm:

Marina86 [1]

57 millimeters..........

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How does a flood change the land

lord [1]

Flood can cause erosion, which is the process of wearing down, and the land can be changed.

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3 years ago

As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

zubka84 [21]

Answer:

$894.12\ \text{N}$

$284.013\ \text{J}$

Explanation:

U = Energy = 76 J

x = Displacement of spring = 0.17 m

k = Spring constant

Energy is given by

$U=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 76}{0.17^2}\\\Rightarrow k=5259.51\ \text{Nm}$

Force is given by

$F=kx\\\Rightarrow F=5259.51\times 0.17\\\Rightarrow F=894.12\ \text{N}$

The magnitude of force must you apply to hold the platform is $894.12\ \text{N}$ .

Now $x=0.17+0.2=0.37\ \text{m}$

$U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 5259.51\times 0.37^2\\\Rightarrow U=360.013\ \text{J}$

Additional energy

$360.013-76=284.013\ \text{J}$

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2 years ago

Please Help!!!!!! What is the acceleration of a car between 2 and 5 seconds? Hint: Acceleration is a change in speed and directi

Ghella [55]

Answer : B. 0 m/s∧2

Now we know that velocity = distance/ time

And acceleration = velocity/time.

From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.

From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.

Now acceleceration between the time interval of 2 ad 5 secs is calculated as

(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2

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2 years ago

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6. A football is kicked with an initial speed of 10.2 m/s at an angle of 40.00 above the horizontal. It lands on the ground 2.12

igor_vitrenko [27]

Answer:

7.81 m/s

Explanation:

Given,

initial speed, u = 10.2 m/s

angle of inclination, θ = 40°

time, t = 2.12 s

Horizontal component of the velocity:

$u_x = u cos \theta$

$u_x = 10.2\times cos 40^0$

$u_x = 7.81 m/s$

In projectile motion horizontal component of the velocity remain same at every point because there is no acceleration.

So, Velocity at the Pinnacle is equal to 7.81 m/s

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2 years ago