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yan [13]
4 years ago
9

Given the redox reaction: Ni + Sn4+ → Ni2+ + Sn2+ Which species has been oxidized?

Chemistry
1 answer:
Vadim26 [7]4 years ago
4 0
Remember this---> LEO=  lose electons oxidation... and GER----> gain electrons reduction

so if you look for the one being oxidized, it is the one losing electrons. since electrons are negative, when an atom lose them, it becomes less negative, so more positive. 

you can identify the oxidization when the atom becomes more positive.

so in the given reaction: <span>Ni + Sn4+ → Ni2+ + Sn2+
</span>
Ni becomes Ni +2   and    Sn+4 becomes Sn+2

as you can see the Ni become Ni+2 so more positive

Ni is being oxidized

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What mass of chromium would be produced from the reaction of 57.0 g of potassium with 199 g of chromium(II) bromide according to
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Answer:

Mass of Chromium produced = 37.91 grams

Explanation:

2K + CrBr₂  →  2KBr + Cr

2mole     1 mole                1 mole

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molar mass of Potassium = 39.1 g/mol

no of moles of Potassium = 57.0 / 39.1 = 1.458 moles

mass of CrBr₂= 199 grams

molar mass of CrBr₂ = 211.8 gram/mole

no of moles of CrBr₂ = 199 / 211.8 = 0.939 mole

From chemical equation

1 mole of CrBr₂ = 2 moles of K

∴ 0.939 moles of CrBr₂ = ?

   ⇒ 0.939 x 2/1 = 1.878 moles of K

1.878 moles of K is needed, but there is 1.458 moles of K. So, Potassium is completed first during the reaction . Hence, Potassium is limiting reagent. and CrBr₂ is excess reagent .

From chemical equation

2 moles of K = 1 mole of Cr

∴ 1.458 moles of K = ?

   ⇒ 1.458 x 1/ 2 = 0.729 moles of Cr

no of moles of Cr formed = 0.729 moles

molar mass of Cr = 52.0 g/mol

mass of one mole of Cr = 52.0 grams

mass of 0.729 moles of Cr = 52.0 x 0.729 = 37.908 grams

mass of Chromium produced = 37.91 grams

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