Answer:
Explanation:
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In this case, for this calorimetry problem, we can notice that the heat evolved by the hot tin is gained by the cold water as the calorimeter is perfectly isolated, so we can write:
Thus, by defining the heats in terms of mass, specific heat and temperatures, we get:
Now, since we are asked for the specific heat of tin, we solve for it as shown below:
Thus, when we plug in, we obtain:
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Answer:
Since all the acid molecules have split into ions, there will be more H+ ions in a strong acid than a weak acid, hence it's pH is lower! E.g. Hydrochloric acid HCl, nitric acid HNO3. If one mole of an acid is neutralised by 2 moles of NaOH, then the acid is dibasic!
Explanation:
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Answer:
-2.79 × 10³ cal
Explanation:
Step 1: Given data
- Mass of water (m): 35.0 g
- Latent heat of fusion of water (L): -79.7 cal/g
Step 2: Calculate the heat required to freeze 35.0 g of water
We have 35.0 g of liquid water and we want to freeze it, that is, to convert it in 35.0 g of ice (solid water), at 0 °C (melting point). We can calculate the heat (Q) that must be released using the following expression.
Q = L × m
Q = -79.7 cal/g × 35.0 g
Q = -2.79 × 10³ cal
It is Newtons Law Of Motion Broski....
