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sweet-ann [11.9K]
3 years ago
9

How many sulfur atoms are in H2SO4?

Chemistry
1 answer:
NemiM [27]3 years ago
6 0

Answer: 1

Explanation:

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PLEASE I NEED THIS ANSWERED IN 5 MINS
yKpoI14uk [10]
The answer would be: C.  160.3 J/mol*K 

To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius

The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K        ------> 1kJ= 1000J
4 0
3 years ago
Question 19 of 25
Flauer [41]
Hypothesis is based on prior knowledge or observations.
8 0
3 years ago
Read 2 more answers
Find the mass in grams of 2.00x10^23 molecules of F2
earnstyle [38]
Hello!

To find the mass in grams of 2.00 * 10²³ molecules of F₂ you'll need to apply the Avogadro's number, which tells the number of molecules in a mol of a substance, and the Molar Mass, which tells the weight of a mole of a substance. These two quantities are used in the following conversion factor:

2,00*10^{23} moleculesF_2* \frac{1 mol F_2}{6,02*10^{23} moleculesF_2 }* \frac{37,997 g F_2}{1 mol F_2} \\  \\ =12,51 g F_2

So, the mass of 2.00 * 10²³ molecules of F₂ is 12,51 g

Have a nice day!
4 0
3 years ago
You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of
motikmotik

Answer:

16.9 mmoles are needed to add to the solution

Explanation:

To solve this, we can apply the Henderson Hasselbach equation:

Acetic acid → CH₃COOH

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻   +  H₃O⁺             Ka

That is the acid base equilibrium, to determine the amount:

pKa of acetic acid is 4.74

Henderson Hasselbach formula is:

pH = pKa + log (base/acid)

We replace  →  4.97 = 4.74 + log (B / 10mmoles)

Let's verify mmoles of B

4.97 - 4.74 = log (B/10)

0.23 =  log (B/10)

10^(0.23) = 10^(log (B/10)

1.698 = B/10

B = 1.698 . 10 → 16.9 mmoles

5 0
3 years ago
3.
zheka24 [161]

Answer:

They are called downbursts.

5 0
3 years ago
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