Answer:
Oxidation process
Explanation:
Oxidation is the transfer of electrons from an atom, molecule, or ion to another atom, molecule, or ion in a chemical reaction.
Oxidation is said to have taken place when the oxidation status of a atom, molecule, or ion is increases.
Oxidation process is said to include
Addition of oxygen atom or Electronegative atoms to another atom, molecule, or ion
Loss of one or more electrons by a atom, molecule, or ion
Increase in the oxidation number of a atom, molecule, or ion
Loss of a hydrogen or Electropositive atoms
Mg (s) ---> Mg²⁺ (aq) + 2e
Co²⁺ (aq) + 2e ---> Co(s)
Cu (s) ---> Cu²⁺ (aq) + 2e
Au²⁺ (aq) + 2e ---> Au(s)
Explanation:
The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. ... is the heat added to, or removed from, the system.
Answer:
D
Explanation:
I hope this right, I'm sorry if it's not.
For an atom to be neutral, it has to have the same amount of protons and electrons. Because protons and electrons have opposite charges, when there is an equal amount of them they balance each other out
Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :
(1) 
(2) 
(3) 
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ
