Atomic # 64
electronic configuration is *[Xe] 6s^2 4f^8
n = 4
ℓ = 3
mℓ<span> = -3</span>
ms<span> = -½</span>
Answer:

Explanation:
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In this case, since the chemical reaction between copper and nitric acid is:

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

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Oxygen 47 Hydrogen 63
Silicon 28 Oxygen 25.5
Aluminum 7.9 Carbon 9.5
Iron 4.5 Nitrogen 1.4
Calcium 3.5 Calcium 0.31
Sodium 2.5 Phosphorus 0.22
Potassium 2.5 Chlorine 0.03
Magnesium 2.2 Potassium 0.06
Titanium 0.46 Sulfur 0.05
Hydrogen 0.22 Sodium 0.03
Carbon 0.19 Magnesium 0.01
All others <0.1 All others <0.01 Living matter
The number of protons and the electron configuration of each