Question

How many moles are there in 987 grams of Ra(OH)2? id also love to know the simplest equation for converting moles --> so i could practice on my own :)

Answer 1

Mole = $\frac{mass}{molar mass}$

Mass of Radium Hydroxide = 987g
Molar Mass of $Ra(OH) _{2}$ = ((226) + (2 * 16) + (2 * 1))
                                            =  260 g / mol

∴  Moles of $Ra(OH) _{2}$ = $\frac{987 g }{ 260 g / mol }$
                                            = 3.796 mols