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dalvyx [7]
2 years ago
15

Using the following combustion reaction, describe how it follows the laws of conservation of mass and energy. CH 4 +2O 2 CO 2 +2

H 2 O+50.1kJ/g .
Chemistry
1 answer:
AURORKA [14]2 years ago
8 0

Answer:

Explanation:

The law of conservation of mass states that "mass in a system remains constant and that the mass of the product is remains the same as that of the reactants".

Law of conservation of energy states that "energy is neither created nor destroyed in the course of chemical or physical change but can be transformed from one form to another".

 Let us properly write the equation:

               CH₄ + 2O₂ → CO₂ + 2H₂O

For the conservation of mass:

  C has 1mole on both sides

   H has 4mole on both sides

   O has 4 mole on both sides

For energy, during combustion process, the methane CH₄ burns to liberate heat energy. This is an energy conversion process in which chemical energy in methane releases heat energy.

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6 0
2 years ago
If 88.0 L of natural gas, which is essentially methane (CH4), undergoes complete combustion at 720. mm Hg and 22ºC, how many gra
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126 grams of H2O is formed.

Explanation:

Data given:

volume of the gas = 88 Liters

pressure = 720 mm Hg or 0.947 atm

temperature T = 22 Degrees or 295.15 K

R = 0.08021 atm L/mole K

n =?

The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation

   = 0.947 X 88/ 0.08021 X 295.15

n = 3.5 moles

balanced reaction for combustion of methane

CH4 + O2  ⇒ CO2 + 2H20

1 mole of CH4 undergoes combustion to form 2 moles of water

3.5 moles will give x moles of water

2/1 = x/3.5

x =  7 moles of water  (atomic mass of water = 18 gram/mole)

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          =126 grams of water is formed.

7 0
3 years ago
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