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dalvyx [7]
3 years ago
15

Using the following combustion reaction, describe how it follows the laws of conservation of mass and energy. CH 4 +2O 2 CO 2 +2

H 2 O+50.1kJ/g .
Chemistry
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

Explanation:

The law of conservation of mass states that "mass in a system remains constant and that the mass of the product is remains the same as that of the reactants".

Law of conservation of energy states that "energy is neither created nor destroyed in the course of chemical or physical change but can be transformed from one form to another".

 Let us properly write the equation:

               CH₄ + 2O₂ → CO₂ + 2H₂O

For the conservation of mass:

  C has 1mole on both sides

   H has 4mole on both sides

   O has 4 mole on both sides

For energy, during combustion process, the methane CH₄ burns to liberate heat energy. This is an energy conversion process in which chemical energy in methane releases heat energy.

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A(g) + 2B(g) → C(g) + D(g)
WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

       A(g) + 2 B(g) ⇄ C(g) + D(g)

I       1.00     1.00        0        0

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E    1.00-x  1.00-2x     x         x

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pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

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