The density is 1.12161 g/ml
<u>Answer:</u> The volume of stock solution needed is 90 mL
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:

where,
are the molarity and volume of the stock sulfuric acid solution
are the molarity and volume of diluted sulfuric acid solution
We are given:

Putting values in above equation, we get:

Hence, the volume of stock solution needed is 90 mL
2 shells because if you do the electronic configuration:
2,7 which adds up to 9
7 stands for the group it in and it also stands for how many electrons are in the outer shell.
the amount of spaces stands for which period its in therefore it in period 2
Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.
<h3>What is the relationship between molar concentration and dilution?</h3>
Molar concentration or the dilution factor is in an inverse relationship and with an increase in the dilution, the molarity of the solution decreases.
Given,
Initial molarity = 2.50 M
initial volume = ?
Final molarity = 0.750 M
Final volume = 100.0 ml
Substituting values in the formula:

Therefore, 30 mL was the initial volume of the solution before it was diluted.
Learn more about dilution here:
brainly.com/question/26896011
Answer:
<h2>pH = 4.44 </h2>
Explanation:
The pH of a substance can be found by using the formula
![p H = - log[ H^{ + } ]](https://tex.z-dn.net/?f=p%20H%20%20%3D%20%20-%20%20%20log%5B%20H%5E%7B%20%2B%20%7D%20%20%5D)
where [ H+ ] is the hydrogen ion concentration of the solution
From the question
[ H + ] = 3.60 × 10^-5 M
So the pH is

We have the final answer as
<h3>pH = 4.44 </h3>
Hope this helps you