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Tpy6a [65]
3 years ago
10

 Some athletes have as little as 3.0% body fat. If such a person has  body  mass of 65 kg,how many pounds of body fat  does  tha

t person have?
 
 
 
Chemistry
1 answer:
coldgirl [10]3 years ago
8 0
They would have 5%:::::)
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A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0
dimaraw [331]

Explanation:

It is known that for high concentration of M^{2+}, reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.

Now, E^{o}_{cell} = 0 and the general reaction equation is as follows.

         M^{2+} + M \rightarrow M + M^{2+}

                3.00 M        n = 2       30 mM

         E = 0 - \frac{0.0591}{2} log \frac{50 \times 10^{-3}}{1}

            = -\frac{0.0591}{2} log (5 \times 10^{-2})

            = 0.038 V

Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.

5 0
3 years ago
What is the name of this alkane?
Otrada [13]
It's a cyclohexane ring with an ethyl group at 1 and a methyl group at 3. The Ethyl group is bigger and more important group get's the first position.

1-ethyl-3-methylcyclohexane
3 0
3 years ago
Read 2 more answers
Naphthalene, C10H8, melts at 80.2°C. If the vapour pressure of the liquid is 1.3 kPa at 85.8°C and 5.3 kPa at 119.3°C, use th
sweet-ann [11.9K]

(a) One form of the Clausius-Clapeyron equation is

ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂); where in this case:

  • P₁ = 1.3 kPa
  • P₂ = 5.3 kPa
  • T₁ = 85.8°C = 358.96 K
  • T₂ = 119.3°C = 392.46 K

Solving for ΔHv:

  • ΔHv = R * ln(P₂/P₁) / (1/T₁ - 1/T₂)
  • ΔHv = 8.31 J/molK * ln(5.3/1.3) / (1/358.96 - 1/392.46)
  • ΔHv = 49111.12 J/molK

(b) <em>Normal boiling point means</em> that P = 1 atm = 101.325 kPa. We use the same formula, using the same values for P₁ and T₁, and replacing P₂ with atmosferic pressure, <u>solving for T₂</u>:

  • ln(P₂/P₁) = (ΔHv/R) * (1/T₁ - 1/T₂)
  • 1/T₂ = 1/T₁ - [ ln(P₂/P₁) / (ΔHv/R) ]
  • 1/T₂ = 1/358.96 K - [ ln(101.325/1.3) / (49111.12/8.31) ]
  • 1/T₂ = 2.049 * 10⁻³ K⁻¹
  • T₂ = 488.1 K = 214.94 °C

(c)<em> The enthalpy of vaporization</em> was calculated in part (a), and it does not vary depending on temperature, meaning <u>that at the boiling point the enthalpy of vaporization ΔHv is still 49111.12 J/molK</u>.

3 0
3 years ago
How many molecules of propane were in the erlenmeyer flask? Avogadro's number is 6. 022 × 10^23 molecules/mol
Ede4ka [16]

3.74×10^{21}

3.74 ×10^{21} molecules of propane were in the erlenmeyer flask.

number of moles of propane can be calculated as moles of propane.

mass of propane =  0.274 g

molar mass of propane = 44.1

So this gives us the value of 6.21×10^{-3} moles of propane

No one mole of propane As a 6.0-2 × 10^{23}

so, 6.21 ×10^{-3} × 6. 022 × 10^23

= 3.74 ×10^{21}

Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×10^{21}

<h3>What is erlenmeyer flask?</h3>
  • A laboratory flask with a flat bottom, a conical body, and a cylindrical neck is known as an Erlenmeyer flask, sometimes known as a conical flask or a titration flask.
  • It bears the name Emil Erlenmeyer after the German chemist.

<h3>What purpose does an Erlenmeyer flask serve?</h3>
  • Liquids are contained in Erlenmeyer flasks, which are also used for mixing, heating, chilling, incubating, filtering, storing, and other liquid-handling procedures.
  • For titrations and boiling liquids, their sloped sides and small necks make it possible to whirl the contents without worrying about spills.

To learn more about calculating total molecules visit:

brainly.com/question/8933381

#SPJ4

4 0
1 year ago
What is the temperature of water at low latitudes please help me
bixtya [17]
The average temperature of the ocean surface waters is about 17 degrees Celsius (62.6 degrees Fahrenheit).

Hoped that helped
6 0
3 years ago
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