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Verizon [17]
3 years ago
6

If a student measured an object's density to be 2.70 g/mL, 2.32 g/mL, 2.12 g/mL and 3.88, then his results would considered ____

__The object's actual density is 3.50 g/mL A. Accurate and precise B.Precise but not accurate C. Neither accurate nor precise D.Accurate but precise
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
5 0

Answer:

C. Neither accurate nor precise

Explanation:

  • The student's results would be considered precise if they were close to one another. However they vary significantly from one another.
  • Regarding accuracy, they would be considered accurate if they were close to the actual value. The given results are too far away from the actual value.

Thus the results are neither accurate nor precise.

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How do newtons 3 laws relate ​
Lina20 [59]

Like all objects, rockets are governed by Newton's Laws of Motion. The First Law describes how an object acts when no force is acting upon it. So, rockets stay still until a force is applied to move them. Newton's Third Law states that "every action has an equal and opposite reaction".

5 0
4 years ago
Atoms containing the same number of protons and different numbers of neutrons are _____. (1 point)
Vadim26 [7]
I believe that it could be isotopes
3 0
4 years ago
Read 2 more answers
The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0
3 years ago
Look at the above table.
MariettaO [177]

Answer:

<em> 1</em>. A. 0

<em>2</em>. B. 7

<em>3. </em>C<em>.</em><em> </em>4

Explanation:

1. charge is equal to the number of protons minus the number of electrons!

2. neutrons is equal to mass number minus atomic number!

3. valence electrons equal 4!

Hope this helped you! :)

7 0
3 years ago
Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels.The heat of combustion of cyclopentane, C5H1
shtirl [24]

Answer : The balanced equation for the complete combustion of cyclopentane will be :

2C_5H_{10}+15O_2\rightarrow 10CO_2+10H_2O

Explanation :

As we know that the hydrocarbons can undergo complete or incomplete combustion that depends on the amount of oxygen available.

Complete combustion : It takes place when there is a good supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon dioxide and water as a product.

The general reaction will be :

\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O

Incomplete combustion : It takes place when there is a poor supply of oxygen. In this, hydrocarbon react with the oxygen to give carbon monoxide, carbon dioxide and water as a product.

The general reaction will be :

\text{Hydrocarbon}+O_2\text{(limited)}\rightarrow CO+CO_2+H_2O

As per question, the complete combustion of cyclopentane react with oxygen to gives carbon dioxide and water as a product.

Therefore, the balanced chemical reaction will be :

2C_5H_{10}+15O_2\rightarrow 10CO_2+10H_2O

7 0
3 years ago
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