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Natali5045456 [20]
4 years ago
8

When elemental iron corrodes it combines with oxygen in the air to ultimately form red brown iron(iii) oxide which we call rust.

(a) if a shiny iron nail with an initial mass of 23.2 g is weighed after being coated in a layer of rust, would you expect the mass to have increased, decreased, or remained the same? explain. (b) if the mass of the iron nail increases to 24.1 g, what mass of oxygen combined with the iron?
Chemistry
1 answer:
iren [92.7K]4 years ago
7 0
<span>The mass of the nail would increase, because the iron is adding oxygen to its chemical composition. This would increase the overall mass. If the mass increases from 23.2g to 24.1g, then the increase would be the difference between the two masses, or 0.9g.</span>
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4 0
3 years ago
A sample of a compound contains 41.33 g of carbon and 8.67 g of hydrogen. The molar mass of the
mihalych1998 [28]

Answer:

C6H15

Explanation:

First, we calculate the empirical formula as follows:

C = 41.33 g

H = 8.67 g

We convert each mass value to mole by dividing each element by its molar mass (C = 12g/mol, H = 1g/mol)

C = 41.33g ÷ 12g/mol = 3.44mol

H = 8.67g ÷ 1g/mol = 8.67mol

Next, we divide each mole value by the smallest (3.44mol)

C = 3.44mol ÷ 3.44mol = 1

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We multiply this ratio by 2 to get a simple whole number ratio

C = 1 × 2 = 2

H = 2.52 × 2 = 5.04

Based on this, the whole number ratio of C and H is 2:5, hence, the empirical formula is C2H5.

The molecular mass of the compound is given as 87.18 g/mol, hence, the molecular formula is calculated as follows:

(C2H5)n = 87.18

[12(2) + 1(5)]n = 87.18

[24 + 5]n = 87.18

(29)n = 87.18

n = 87.18 ÷ 29

n = 3.006

Approximately to whole number, n = 3

Hence, the molecular formula of the compound is [C2H5]3

= C6H15

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3 years ago
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AysviL [449]

Answer:

It’s B - CO

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GenaCL600 [577]

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Answer:

D It affects the heart

Explanation:

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