Question

In the fermentation of glucose (wine making), 790 mL of CO2 gas was produced at 37 ∘C and 1.00 atm . You may want to reference (Pages 303 - 304) Section 8.5 while completing this problem. Part A What is the final volume, in liters, of the gas when measured at 18 ∘C and 695 mmHg , when n is constant?

Answer 1

Answer: The volume of the gas when the pressure and temperature has changed is  0.811 L

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

Conversion factor used:

1 L = 1000 mL

1 atm = 760 mmHg

$P_1=1.00atm=760mmHg\\V_1=790mL=0.790L\\T_1=37^oC=[37+273]K=310K\\P_2=695mmHg\\V_2=?L\\T_2=18^oC=[18+273]K=291K$

Putting values in above equation, we get:

$\frac{760mmHg\times 0.790L}{310K}=\frac{695mmHg\times V_2}{291K}\\\\V_2=\frac{760\times 0.790\times 291}{310\times 695}=0.811L$

Hence, the volume of the gas when the pressure and temperature has changed is 0.811 L