All categories

3 years ago

Why is Iron found as an Ore in the Earth

Chemistry

1 answer:

Stella [2.4K]3 years ago

7 0

$\huge \orange {\mathbb {Answer}}$

Ore is a deposit in Earth's crust of one or more valuable minerals. The most valuable ore deposits contain metals crucial to industry and trade, like copper, gold, and iron. Copper ore is mined for a variety of industrial uses. Copper, an excellent conductor of electricity, is used as electrical wire.

You might be interested in

Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.85 M of reagent

elixir [45]

Answer : The initial rate for a reaction will be $3.8\times 10^{-4}Ms^{-1}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The chemical equation will be:

$A+B+C\rightarrow P$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.1\times 10^{-5}=k(0.2)^a(0.2)^b(0.2)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-4}=k(0.2)^a(0.2)^b(0.6)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-4}=k(0.4)^a(0.2)^b(0.2)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-4}=k(0.4)^a(0.4)^b(0.2)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.2)^a(0.2)^b(0.6)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.4)^a(0.2)^b(0.2)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.4)^a(0.4)^b(0.2)^c}{k(0.4)^a(0.2)^b(0.2)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$6.1\times 10^{-5}=k(0.2)^2(0.2)^0(0.2)^1$

$k=7.6\times 10^{-3}M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 0.85 M of reagent A and 0.70 M of reagents B and C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(7.6\times 10^{-3})\times (0.85)^2(0.70)^0(0.70)^1$

$\text{Rate}=3.8\times 10^{-3}Ms^{-1}$

Therefore, the initial rate for a reaction will be $3.8\times 10^{-3}Ms^{-1}$

6 0

3 years ago

Use the "x is small" approximation to find the concentration of the products in the following reaction which initially contains

Mrrafil [7]

Answer:

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

$[CN^-]=0.0000229 M$

Explanation:

$HCN(aq)\rightleftharpoons H^+(aq) + CN^-(aq)$

initially

0.85 M 0 0

(0.85-x)M x x

The equilibrium constant of reaction = $K_c= 6.17\times 10^{-10}$

The expression of an equilibrium cannot can be written as:

$K_c=\frac{[H^+][CN^-]}{[HCN]}$

$6.17\times 10^{-10}=\frac{x\times x}{(0.85-x)}$

Solving for x:

x = 0.0000229

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

$[CN^-]=0.0000229 M$

4 0

2 years ago

Irma has $500 to open a checking account. She wants an account with the lowest fees. She plans to use only her bank's ATM to

Archy [21]

the answer is account A

8 0

2 years ago

Read 2 more answers

25 POINTS! Which traits are characteristic of both single-celled and multicellular organisms? Choose all answers that are correc

worty [1.4K]

The answer is d. The answer is that because both of them can reproduce that way.

3 0

3 years ago

Read 2 more answers

Suppose you were to make a ring from a single strand of gold atoms. How many gold atoms would be required to make such a ring? H

Rudiy27

Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:

54.3 mm = 5.43 cm

Now, we determine the number of gold atoms that will be present in this:

5.43 / 1 x 10⁻⁹

There will be 5.43 x 10⁹ atoms

We now determine the number of moles this is by:

one mole = 6.02 x 10²³ atoms

Moles = 5.43 x 10⁹ / 6.02 x 10²³
Moles = 9.01 x 10⁻¹⁵ moles

The molar mass of gold is 197 g/mol

The mass is 9.01 x 10⁻¹⁵ * 197

The mass of the strand is 1.76 x 10⁻¹² grams

8 0

2 years ago

Read 2 more answers