Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.
1) Zn(CH₃COO)₂(s) + 2KOH(aq) = Zn(OH)₂(s) + 2CH₃COOK(aq)
Ksp{Zn(OH)₂}=1.2*10⁻¹⁷
2) Zn(CH₃COO)₂(s) + 2NaCN(aq) = Zn(CN)₂(s) + 2CH₃COONa(aq)
Ksp{Zn(CN)₂}=2.6*10⁻¹³
Ksp{Zn(OH)₂}<Ksp{Zn(CN)₂}
Zn(OH)₂ precipitates first
Answer:
V = 48.5 L
Explanation:
Converting °C to K and kPa to atm
T = 25.0°C + 273.15 = 298.15 K
P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm
Calculating the volume of gas
V = nRT / P
V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm
V = 48.5 L
Answer:
c. salty.
Explanation:
From the question,
The reaction of an acid , i.e hydrochloric acid and a base i.e. , sodium hydroxide takes place , which is a type of neutralization reaction,
Where the acid and a base reacts to give salt along with water .
From the question,
The reaction is as follows -
2 HCl + NaOH → NaCl + H₂O
Hence, the resulting product is a salt ,
Therefore , the resulting solution would taste like salt.
