All categories

2 years ago

Which one of the following substances is a solution?

Chemistry

2 answers:

Nostrana [21]2 years ago

7 0

Hdhdhdjdndjsjshshshhd

Sphinxa [80]2 years ago

4 0

A . Clay this solution is used in old buildings

You might be interested in

How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci

horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0

3 years ago

A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. What was its acceleration?

Zigmanuir [339]

Acceleration is defined as velocity per unit time.

$Acceleration=\frac{Velocity}{time}$

$a=\frac{dv}{dt}$

Here, a=acceleartion,

v=velocity=36 m/s

t=time=12 s

$a=\frac{dv}{dt}$

$a=\frac{36}{12}$

$a=3 ms⁻²$

A car at rest ends accelerates for 12 seconds. After this time the car is going 36 m/s. So acceleration that is a=3 ms⁻².

4 0

3 years ago

Read 2 more answers

A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO

NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity, μg

N₀ = Original quantity, μg

λ= Decay constant day⁻¹

t = time in days

Since the half life is 4.5 days, we can calculate the λ from (1) by substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5 = -4.5λ

-0.6931 = -4.5λ

λ = -0.6931 /-4.5

=0.1540 day⁻¹

Substituting into (1) we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀] = exp (-0.154 x 1)

5/N₀ = 0.8572

N₀ = 5/0.8572

= 5.8329μg

≈ 5.8μg

The Chemist must order 5.8μg of 47-CaCO3

6 0

2 years ago

PLEASE HELP ME WITH PHYSICAL SCIENCE!! PRETTY EASY QUESTION

Umnica [9.8K]

Explanation:

Bbbbbbbbbbbbbbbbbbbbb

7 0

2 years ago

Read 2 more answers

What is the purpose of light energy?

zimovet [89]

The sun gives off light energy to help plants photosynthesize and make food

8 0

2 years ago