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rewona [7]
3 years ago
7

A solution of 400mg of optically active 2-butanol in 10 mL of water, placed in a 20 cm cell shows an optical rotation of 40o. Wh

at is the specific rotation of this compound?
Chemistry
1 answer:
labwork [276]3 years ago
3 0

Answer:

Specififc rotation [∝] = 0.5° mL/g.dm

Explanation:

Given that:

mass = 400 mg

volume = 10 mL

For a solution,

The Concentration = mass/volume

Concentration = 400/10

Concentration = 40 g/mL

The path length l = 20 cm = 2 dm

Observed rotation [∝] = + 40°

Specififc rotation [∝] = ∝/l × c

where;

l = path length

c = concentration

Specififc rotation [∝] = (40 / 2 × 40)

Specififc rotation [∝] = 0.5° mL/g.dm

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If 24 g rams of ozone, 03, was collected how many moles were collected?
dexar [7]

Hey there!

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therefore:

1 mole O₃ ---------------------  47.9982 g

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moles O₃ = 24 x 1 /  47.9982

moles O₃ = 24 / 47.9982

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Hope this helps!

5 0
3 years ago
When 10 grams of copper and 10 grams of iodine are mixed, what is the
PtichkaEL [24]
<h2>Answer:</h2>

<em>Third option is correct, 7.5 grams of CuI.</em>

<h3>Explanation:</h3>

Given data :

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Limiting reactant : I2

So Moles of CuI produced =  0.039 mol.

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5 0
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RUDIKE [14]

Answer: I don’t know lol

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