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Nesterboy [21]
4 years ago
12

For the following reaction, 5.22 grams of aluminum oxide are mixed with excess sulfuric acid. The reaction yields 12.9 grams of

aluminum sulfate. aluminum oxide (s) + sulfuric acid (aq) aluminum sulfate (aq) + water (l) What is the theoretical yield of aluminum sulfate ?
Chemistry
1 answer:
Mamont248 [21]4 years ago
6 0

Answer:

m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Explanation:

Hello,

In this case, the undergoing balanced chemical reaction is:

Al_2O_3(s)+3H_2SO_4(aq)\rightarrow Al_2(SO_4)_3(aq)+3H_2O(l)

Thus, as 5.22 grams of aluminium oxide reacts, the required yielded amount of aluminium sulfate results:

m_{Al_2(SO_4)_3}=5.22gAl_2O_3*\frac{1molAl_2O_3}{102gAl_2O_3}*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3}*\frac{342gAl_2(SO_4)_3}{1molAl_2(SO_4)_3} \\\\m_{Al_2(SO_4)_3}=17.5gAl_2(SO_4)_3

Moreover, the percent yield is:

Y=\frac{12.9g}{17.5g} *100\%=73.7\%

Best regards.

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What is the pH of an aqueous solution of 1 M CH3COOH (pKa=4)
Mrac [35]

Answer:

pH = 2.

Explanation:

A weak acid is in equilibrium with its ions in a solution, so it must have an equilibrium constant (Ka). And, pKa = -logKa

Ka = 10^{-pKa}

Ka = 10⁻⁴

So, for CH₃COOH the equilibrium must be:

CH₃COOH(aq) ⇄ H⁺(aq) + CH₃COO⁻(aq)

1 M                           0                0                Initial

-x                              +x              +x               Reacted

1-x                             x                x                 Equilibrium

And the equilibrium constant:

Ka = \frac{[H+]x[CH3COO-]}{[CH3COOH]}

10^{-4} = \frac{x^2}{1-x}

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x = √10⁻⁴

x = 10⁻² M, so the supposing is correct.

So,

pH = -log[H⁺]

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8 0
4 years ago
A sample that contains aluminum is reacted with sulfuric acid according to the equation given below. When the aluminum dissolves
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Answer:

m_{H_2}=0.0574gH_2

Explanation:

Hello,

In this case, the information about the pressure, volume and temperature are enough to compute the mass of hydrogen assuming its ideal behavior:

n_{H_2}=\frac{PV}{RT}=\frac{739mmHg*\frac{1atm}{760mmHg}*0.722 L}{0.082 \frac{atm*L}{mol*K}*298.15K} =0.0287molH_2

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m_{H_2}=0.0287molH_2*\frac{2gH_2}{1molH_2} \\m_{H_2}=0.0574gH_2

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A voltaic cell is constructed with an Fe/Fe²⁺ half-cell and an Mn/Mn²⁺ half-cell. The iron electrode is positive.(a) Write balan
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<h3>What does the term "redox reaction" mean?</h3>

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