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Komok [63]
3 years ago
5

Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical

Chemistry
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

2H_2O\rightarrow 2H_2+O_2

Explanation:

Hello there!

In this case, for the reaction by which water is decomposed to molecular hydrogen and oxygen:

H_2O\rightarrow H_2+O_2

It is necessary to perform the inspection balance process since there is a dissimilar number of atoms of oxygen on both sides; therefore, by putting a 2 on water we balance oxygen:

2H_2O\rightarrow H_2+O_2

But now, there are four hydrogens on the left; therefore, we put a 2 on hydrogen to finally balance it:

2H_2O\rightarrow 2H_2+O_2

And obviously, the coefficient in oxygen is an unwritten 1.

Best regards!

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[HELP PLEASE] Describe the difference between the ways valence electrons are rearranged when forming ionic bonds and covalent bo
nydimaria [60]

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2 years ago
Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

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Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
2 years ago
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