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Komok [63]
3 years ago
5

Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical

Chemistry
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

2H_2O\rightarrow 2H_2+O_2

Explanation:

Hello there!

In this case, for the reaction by which water is decomposed to molecular hydrogen and oxygen:

H_2O\rightarrow H_2+O_2

It is necessary to perform the inspection balance process since there is a dissimilar number of atoms of oxygen on both sides; therefore, by putting a 2 on water we balance oxygen:

2H_2O\rightarrow H_2+O_2

But now, there are four hydrogens on the left; therefore, we put a 2 on hydrogen to finally balance it:

2H_2O\rightarrow 2H_2+O_2

And obviously, the coefficient in oxygen is an unwritten 1.

Best regards!

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Which of the following increases the reaction rate? A. Adding a catalyst to the reaction mixture B. Increasing the size of solid
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A. Adding a catalyst. A catalyst by definition is a compound that speeds up reaction rates.
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Compare the density of the ocean crust and the continental crust. If they were to collide, predict which one would push under th
uysha [10]

Answer:

The difference between the density of the ocean crust and the continental crust is the fact that the ocean crust is denser than the continental crust. Meaning, the continental crust is likely to push over the oceanic crust considering it has less dense.

Explanation:

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Relate what you have learned about the word quantum to the Bohr model.​
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7 0
2 years ago
A sample of a gas at 25°C has a volume of 150 mL when its pressure is 0.947 atm. What will the temperature of the gas be at a pr
dezoksy [38]

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂

5.682 = 142.128/T₂

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6 0
2 years ago
What mass of F2 is needed to produce 180 g of PF3 if the reaction has a 78.1% yield?
nexus9112 [7]

Answer:

91.26 g

Explanation:

Given data:

Mass of PF₃ = 180 g

Mass of F₂ required = ?

Solution:

Chemical equation:

P₄ + 6F₂   → 4PF₃

Moles of PF₃:

Number of moles = mass/ molar mass

Number of moles = 180 g/ 88 g/mol

Number of moles = 2.05 mol

Now we will compare the moles of PF₃ with F₂.

                        PF₃            :           F₂

                          4               :           6

                          2.05         :           6/4×2.05 = 3.075

Mass of  F₂:

Mass of F₂ = moles × molar mass

Mass of F₂ = 3.075 mol × 38 g/mol

Mass of F₂ =  116.85 g

If reaction yield is 78.1%:

116.85 /100 ×78.1 = 91.26 g

6 0
2 years ago
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