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Tatiana [17]
3 years ago
8

The nitrogen atoms in N2 participate in multiple bonding whereas those in hydrazine, N2H4, do not. a.) Draw Lewis structures for

both molecules. b.) What is the hybridization of the nitrogen atoms in each molecule? c.) Which molecule has a stronger N-N bond?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

a) Attached images.

b) N₂: sp; N₂H₄: sp³

c) N₂

Explanation:

a) In the attached images are the Lewis structures.

<em>N₂:</em> there is a triple covalent bond between the N atoms.

<em>N₂H₄:</em> there is a single covalent bond between the N atoms.

b)

<em>N₂:</em> N has 2 electron domains. The corresponding hybridization is sp.  1 sp orbital form 1 sigma bonds whereas 2 p orbitals from 2 pi bonds.

<em>N₂H₄:</em> N has 4 electron domains. The corresponding hybridization is sp³. The 3 sp³ orbitals form 3 sigma bonds.

c) The triple bond is stronger than the single bond. Then, the bond in N₂ is stronger than the bond in N₂H₄.

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