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7nadin3 [17]
3 years ago
12

Would precipitation occur when 500 mL of a 0.02M solution of AgNO3 is mixed with 500 mL of a 0.001M solution of NaCl? Show your

work.
Chemistry
1 answer:
Oksanka [162]3 years ago
7 0
We know,
AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate
You might be interested in
Classify each of these reactions. A single reaction may fit more than one classification. Ba ( ClO 3 ) 2 ⟶ BaCl 2 + 3 O 2 Ba(ClO
Lena [83]

Answer: a) Ba(ClO_3)_2\rightarrow BaCl_2+3O_2:  Decomposition

b) NaNO_2+HCl\rightarrow NaCl+HNO_2: double displacement

c) CaO+CO_2\rightarrow CaCO_3: Synthesis (Combination)

d) ZnSO_4+Mg\rightarrow MgSO_4+Zn: redox

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

Ba(ClO_3)_2\rightarrow BaCl_2+3O_2

A double displacement reaction is one in which exchange of ions take place.

NaNO_2+HCl\rightarrow NaCl+HNO_2

Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

CaO+CO_2\rightarrow CaCO_3

Redox reaction is a type of chemical reaction in which oxidation and reduction takes place in one single reaction. The oxidation number of one element increases and the oxidation number of other element decreases.

ZnSO_4+Mg\rightarrow MgSO_4+Zn

4 0
3 years ago
Who was the first person to propose that atoms existed?
Gennadij [26K]
Democritus was the first person to theorize the existence of atoms.
8 0
3 years ago
Read 2 more answers
The equilibrium constant for the gas-phase isomerization of borneol (c10h17oh) to isoborneol at 503 k is 0.106. a mixture consis
Dimas [21]
The solution is as follows:

K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106

The molar mass of isoborneol/borneol is 154.25 g/mol

Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol

Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
E     0.0972 - x        0.0486 + x

Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
6 0
3 years ago
2) what is the mass of 6.02 x 1023 atoms of arsenic?
zzz [600]
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>

Solving:

1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule

6,02*10²³X = 75
x = \frac{75}{6,02*10^{23}}
\boxed{x \approx 1,24*10^{24}grams}
6 0
3 years ago
Helppppppppppp please
valentinak56 [21]
Your answer would have to be #3
4 0
3 years ago
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