Polarity is classified by the difference in two or more atoms that is the electronegativity value (EN) En for Fluorine =4.0, Bromine=2.96 Chlorine =3.16 Hydrogen=2.1 for the molecules HF=4.0-2.I=1.9 HCl=3.16-2.1=1.06 Hbr=2.96-2.1=0.86 Hi=2.66-2.1=0.56 H2=2.1-2.1=0 from the EN value above HF has the mast highest value of EN hence it is the most polar.
The compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.
Explanation:
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To calculate the electronegativity of the compounds, the difference in electronegativity of each of the elements is calculated.
The data we need are:
Fluorine = 4.0
Chlorine = 3.16
Hydrogen = 2.1
Bromine = 2.96
Iodo = 2.66
The electronegativity of the compounds is:
HI: 2.66-2.1 = 0.56
HBr: 2.96-2.1 = 0.86
H2: 2.1-2.1 = 0
HF: 4-2.1 = 1.9
HCl: 3.16-2.1 = 1.06
After the calculations, we can conclude that the compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.
The middle of the nucleus contains the protons and the neutrons which contain the positive and electrical charges which decides the element which means option C will be your answer.
