Question

Of the molecules below, the bond in ________ is the most polar. of the molecules below, the bond in ________ is the most polar. hi hbr h2 hf hcl

Answer 1

Polarity   is  classified by  the  difference  in  two  or  more  atoms that  is  the electronegativity  value (EN)
En  for  Fluorine =4.0,  Bromine=2.96 Chlorine =3.16  Hydrogen=2.1
for  the molecules
HF=4.0-2.I=1.9
HCl=3.16-2.1=1.06
Hbr=2.96-2.1=0.86
Hi=2.66-2.1=0.56
H2=2.1-2.1=0
from  the  EN  value above  HF  has  the  mast  highest  value  of  EN  hence  it  is  the  most  polar.

Answer 2

Answer:

The compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

Explanation:

Hello!

Let's solve this!

To calculate the electronegativity of the compounds, the difference in electronegativity of each of the elements is calculated.

The data we need are:

Fluorine = 4.0

Chlorine = 3.16

Hydrogen = 2.1

Bromine = 2.96

Iodo = 2.66

The electronegativity of the compounds is:

HI: 2.66-2.1 = 0.56

HBr: 2.96-2.1 = 0.86

H2: 2.1-2.1 = 0

HF: 4-2.1 = 1.9

HCl: 3.16-2.1 = 1.06

After the calculations, we can conclude that the compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.