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RideAnS [48]
3 years ago
12

Of the molecules below, the bond in ________ is the most polar. of the molecules below, the bond in ________ is the most polar.

hi hbr h2 hf hcl
Chemistry
2 answers:
Goryan [66]3 years ago
6 0
Polarity   is  classified by  the  difference  in  two  or  more  atoms that  is  the electronegativity  value (EN)
En  for  Fluorine =4.0,  Bromine=2.96 Chlorine =3.16  Hydrogen=2.1
for  the molecules
HF=4.0-2.I=1.9
HCl=3.16-2.1=1.06
Hbr=2.96-2.1=0.86
Hi=2.66-2.1=0.56
H2=2.1-2.1=0
from  the  EN  value above  HF  has  the  mast  highest  value  of  EN  hence  it  is  the  most  polar.
NemiM [27]3 years ago
4 0

Answer:

The compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

Explanation:

Hello!

Let's solve this!

To calculate the electronegativity of the compounds, the difference in electronegativity of each of the elements is calculated.

The data we need are:

Fluorine = 4.0

Chlorine = 3.16

Hydrogen = 2.1

Bromine = 2.96

Iodo = 2.66

The electronegativity of the compounds is:

HI: 2.66-2.1 = 0.56

HBr: 2.96-2.1 = 0.86

H2: 2.1-2.1 = 0

HF: 4-2.1 = 1.9

HCl: 3.16-2.1 = 1.06

After the calculations, we can conclude that the compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

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The half life of a radioactive element is 2 million years. a mass of rock originally contained 200g of this element. how many gr
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Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
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