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Paraphin [41]
2 years ago
5

A solution is made by mixing equal masses of methanol, CH4O, and ethanol, C2H6O. Determine the mole fraction of each component t

o at least three signA solution is made by mixing equal masses of methanol, CH4O, and ethanol, C2H6O. Determine the mole fraction of each component to at least three significant figures.ificant figures.
Chemistry
1 answer:
Serggg [28]2 years ago
5 0

Answer: mole fraction of methanol = 0.590

mole fraction of ethanol = 0.410

Explanation:

We are given:

Equal masses of methanol CH_4O and ethanol C_2H_6O are mixed.

let the mass be x g.

Calculating the moles of methanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{32.04g/mol}

Calculating the moles of ethanol in the solution, by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{xg}{46.07g/mol}

To calculate the mole fraction of methanol, we use the equation:

\chi_{methanol}=\frac{n_{methanol}}{n_{methaol}+n_{ethanol}}

\chi_{methanol}=\frac{\frac{xg}{32.04g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.590

To calculate the mole fraction of ethanol, we use the equation:

\chi_{ethanol}=\frac{n_{ethanol}}{n_{methaol}+n_{ethanol}}

\chi_{ethanol}=\frac{\frac{xg}{46.07g/mol}}{\frac{xg}{32.04g/mol}+\frac{xg}{46.07g/mol}}=0.410

Thus mole fraction of methanol is 0.590 and mole fraction of ethanol 0.410 in three significant figures.

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mafiozo [28]

Answer:

A crystal or crystalline solid is a solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions. The scientific study of crystals and crystal formation is known as crystallography.

Explanation:

3 0
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2 kg nitrogen reacts with 1 kg hydrogen.calculate the mass of ammonia
liubo4ka [24]
2<span> NH3 the ratio between N2 and H2 is </span>1<span> : 3 ... actual moles H2 = 5000 g / </span>2<span> g/mol=2500 so H2 is the limiting reactant</span>
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6. If concentrations measured in moles per liter, and time in seconds, what are the units of the rate constant for (a) a first o
kaheart [24]

Answer:

(a) a first order reaction = s^-1.

(b) a second-order reaction = L(mol·s)

(c) a third-order reaction = s⁻¹M⁻²

Explanation:

Okay, this question is a question that has to do with kinetics that is how reaction occurs.

So, the RATE LAW is one of the concept that is being used in determining conditions of chemical reactions. The relationship between the the reactants molarity and the reaction rate is known as rate law. That is to say;

Rate law = K × Molarity.

So, In this question we are given that the concentrations measured in moles per liter, and time in seconds.

The FIRST ORDER REACTION has its unit for rate constant as per seconds(s^-1).

That is from; Rate law = k

Molarity/s = k × Molarity.

k = s^-1

(b) a second-order reaction;

Rate law= k × (molarity)^2.

Molarity/s = k × (Molarity)^2.

k = L(mol·s)

(c) A third-order reaction = s⁻¹M⁻²

Same thing applies.

5 0
3 years ago
Read 2 more answers
A 2.51 times 10^-2 L sample of a solution of Cu^ requires 3.30 times 10^-2 L of 0.132 M KMnO_4 solution to reach the equivalence
sergejj [24]

Answer:

0.868M Cu⁺

Explanation:

The reaction is:

KMnO₄ + 5Cu⁺ + 8H⁺ → 5Cu²⁺ + Mn²⁺ + K⁺ + 4H₂O

<em>Where 1 mol of KMnO₄ reacts with 5 moles of Cu⁺</em>

<em />

3.30x10⁻²L of 0.132M KMnO₄ are:

3.30x10⁻²L ×  (0.132mol KMnO₄ / L) = <em>4.356x10⁻³mol KMnO₄</em>

As 1 mol reacts with 5 moles of Cu⁺, moles of Cu⁺ are:

4.356x10⁻³mol KMnO₄ × (5mol Cu⁺ / 1mol KMnO₄) = <em>0.02178moles Cu⁺</em>

As these moles are in 2.51x10⁻²L, the starting concentration of the Cu⁺ solution is:

<em>0.02178moles Cu⁺ / </em>2.51x10⁻²L = <em>0.868M Cu⁺</em>

3 0
3 years ago
2. (RI 1.3) What connection does the author draw between the way humans would be
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Answer:D

Explanation:

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