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MArishka [77]
3 years ago
13

NUMBERS 6-8 URGENT PLEASE

Chemistry
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

See explanation

Explanation:

9g of water contains : 9g/18 g/mol = 0.5 mole of water

1) 2 moles of hydrogen yields 2 moles of water

x moles of hydrogen yields 0.5 moles of water

x= 2 × 0.5/2 = 0.5 moles of hydrogen

Mass of hydrogen = 0.5 moles × 2 = 1 g of hydrogen

2) Number of moles of Al(OH)3 = 468 g/ 78 g/mol = 6 moles

2 moles of Al(OH)3 yields 3 moles of H2O

6 moles of Al(OH)3 yields 6 × 3/2 = 9 moles of H20

Mass of water =9 moles × 18 g/mol = 162 g of water

3) There are 13 oxygen atoms in the compound.

Mass of each oxygen atom = 16 g

Total mass of oxygen atoms = 13 × 16 = 208 g

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Ivahew [28]

Answer:

to mi understanding iz fusion reaction

6 0
3 years ago
An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese ru
HACTEHA [7]

Rusting is an electrochemical reaction. Iron rusts faster when alloyed with cobalt than when alloyed with manganese because, in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

An alloy is a combination of two metals. There are various reasons for producing alloys such as greater tensile strength, corrosion resistance and improved aesthetic appearance.

When iron is alloyed with cobalt, the iron rusts faster than pure iron because iron is rendered the anode and cobalt is rendered the cathode. When the iron is alloyed with manganese, it rusts more slowly than pure iron because in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode.

Missing parts;

An iron object alloyed with cobalt rusts more quickly than a pure iron object. However, an iron object alloyed with manganese rusts less quickly than a pure iron object under the same conditions. This is true because

(1) cobalt is a stronger reducing agent than iron

(2) iron is a stronger reducing agent than manganese

(3) cobalt exhibits more metallic character than either iron or manganese

(4) in the iron-manganese alloy, manganese is rendered the anode and iron is rendered the cathode

(5) in the iron-cobalt alloy, cobalt is rendered the anode and iron is rendered the cathode

Learn more: brainly.com/question/14281129

5 0
3 years ago
Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno
Arada [10]

Answer:

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

Explanation:

CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate =\frac{14.220 g}{(159.5+n\times 18) g/mol}

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = \frac{8.9935 g}{159.5 g/mol}

\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

5 0
3 years ago
I have this chemistry question and I’m really struggling to answer it. Can someone please help me figure out the steps & the
Digiron [165]

Answer: 133,333.333 meters.

Explanation:

I forgot how to explain this looool.

7 0
3 years ago
0.50 g of hydrogen chloride (HCl) is dissolved in water to make 4.0 L of solution. What is the pH of the resulting hydrochloric
svlad2 [7]

Explanation:

Given the mass of HCl is ---- 0.50 g

The volume of solution is --- 4.0 L

To determine the pH of the resulting solution, follow the below-shown procedure:

1. Calculate the number of moles of HCl given by using the formula:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}

2. Calculate the molarity of HCl.

3. Calculate pH of the solution using the formula:

pH=-log[H^+]

Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

HCl(aq)->H^+(aq)+Cl^-(aq)

Thus, [HCl]=[H^+]

Calculation:

1. Number of moles of HCl given:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}\\=0.50g/36.5g/mol\\=0.0137mol

2. Concentration of HCl:

Molarity of HCl=\frac{number of moles of HCl}{its molar mass}\\=\frac{0.0137 mol}{4.0 L} \\= 0.003425 M

3. pH of the solution:

pH=-log[H^+]\\=-log(0.003425)\\=2.47

Hence, pH of the given solution is 2.47.

3 0
3 years ago
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