Question

E (-2,3) F (0,4) G (2,3) Rhombus EFGH has the coordinates shown. Find the coordinates of point H.

Answer 1

H would be (0,2) if it is a Rhombus

Answer 2

Answer:

Coordinates of point H is (0,2).

Step-by-step explanation:

Given the co-ordinates of rhombus which are E (-2,3), F (0,4), G (2,3). We have to find the coordinate of point H.

let coordinate of point H are (a,b).

Now, as diagonals of rhombus bisect each other.

⇒ O is the mid-point of HF and EG.

Hence, by mid-point formula

$(\frac{0+a}{2},\frac{4+b}{2})=(\frac{2-2}{2},\frac{3+3}{2})\\\\(\frac{a}{2},\frac{4+b}{2})=(0,3)$

⇒ $\frac{a}{2}=0$,   $\frac{4+b}{2}=3$

⇒ $a=0$,               $4+b=6$

⇒ (a,b)=(0,2)

Hence, coordinates of point H is (0,2).