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guapka [62]
3 years ago
9

Leah watches a toy car move across a table at a constant speed. The car moves across the table in one direction and falls off th

e other side. Leah decides to try another situation. She watches the car move across the table at a constant speed, then when it reaches the other side of the table, her friend Joey pushes the car in the other direction. The car moves back to Leah.
Based on Leah's informal experiment, what forces cause the car to change direction?
A.
balanced forces from Joey pushing the car
B.
unbalanced forces from Joey pushing the car
C.
unbalanced forces from Leah watching the car
D.
balanced forces from the car moving across the table
Physics
2 answers:
Sedbober [7]3 years ago
5 0

In order to change the direction and speed, a net external force is required. A net external force is an unbalanced force which will change the direction and gives the speed in the opposite direction. Hence, its an unbalanced force from the joey that pushes the car in the other direction due to which it the car starts to move back to Leah. Without, unbalanced force there is not change in the direction of the car's motion.

Hence, option B is correct.

zalisa [80]3 years ago
5 0

Answer:

B

Explanation:

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2 years ago
You normally drive a 12-h trip at an average speed of 100 km/h . Today you are in a hurry. During the first two-thirds of the di
kherson [118]

Answer:

78 km/h

Explanation:

If I normally drive a 12 hour trip at an average speed of 100 km/h, my destination has a total distance of:

  • 100 km/h · 12 h = 1,200 km

Today, I drive the first 2/3 of the distance at 116 km/h. Let's first calculate what 2/3 of the normal distance is.

  • 1,200 * 2/3 = 800 km

I've driven 800 km already. I need to drive 400 km more to reach my final destination. I need to figure out my average speed during this last 1/3 of the distance.

To do this, I first need to calculate how much time I spent driving 116 km/h for the past 800 km.

  • 116 km/1 h = 800 km/? h
  • 800 = 116 · ?
  • ? = 800/116
  • ? = 6.89655172

I spent 6.89655172 hours driving during the first 2/3 of the distance.

Now, I need to subtract this value from 12 hours to find the remaining time I have left.

  • 12 h - 6.89655172 h = 5.10344828 h  

Using this remaining time and my remaining distance, I can calculate my average speed.

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My average speed during the last third of the distance is around 78 km/h.

8 0
2 years ago
If a space probe sends back info on an object traveling through space at close to the speed of light astronomers will be working
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3 years ago
A charged capacitor is connected to an ideal inductor. At time t = 0, the charge on the capacitor is equal to 6.00 μC. At time t
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Answer:

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Q_{max} = Maximum charge stored by capacitor = 6 μC = 6 x 10⁻⁶ C

t  = time taken for charge on the capacitor to become zero = 2 ms = 2 x 10⁻³ s

Time period is given as

T = 4t

T = 4(2\times 10^{-3})

T = 8\times 10^{-3} s

Angular frequency is given as

w = \frac{2\pi }{T}

w = \frac{2(3.14) }{8\times 10^{-3}}

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Taking derivative both side relative to "t"

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i_{max}= 4.71\times 10^{-3}A

8 0
3 years ago
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