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2 years ago

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A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the e

quation x(t)= α t2− β t3, where α = 1.42m/s2 and β = 5.00×10−2m/s3 .. Calculate the average velocity of the car for the time interval t=0 to t1 = 2.08s

1 answer:

andrew-mc [135]2 years ago

3 0

Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s

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