A physical property is any property that is measurable, whose value describes a state of a physical system. The changes in the physical properties of a system can be used to describe its changes between momentary states. Physical properties are often referred to as observables. They are not modal properties.
Answer:
0.0917 mol Co(CrO₄)₃
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
37.3 g Co(CrO₄)₃
<u>Step 2: Identify Conversions</u>
Molar Mass of Co - 58.93 g/mol
Molar Mass of Cr - 52.00 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Co(CrO₄)₃ - 58.93 + 3(52.00) + 12(16.00) = 406.93 g/mol
<u>Step 3: Convert</u>
<u />
= 0.091662 mol Co(CrO₄)₃
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.091662 mol Co(CrO₄)₃ ≈ 0.0917 mol Co(CrO₄)₃
At l = 3, ml =+3,+2,+1,0,-1,-2,-3
What are quantum numbers?
- Quantum numbers are used to describe where around a nucleus a particular electron can be found.
- In any given atom, each electron can be described by four quantum numbers.
- These are n,l,m1,ms
- The values that each number can be are based on a set of rules.
What is a magnetic quantum number ?
- It describes the orientation of the orbitals.
- It is represented as ml.
- The value of this quantum number ranges from (-l to +l).
- When l = 2, the value of will be -2, -1, 0, +1, +2.
To know more about magnetic quantum numbers, refer:
brainly.com/question/14650566
#SPJ4
Answer:
DECREASE BY A FACTOR OF FOUR
Explanation:
Using pressure equation:
P 1 / T1 = P2 /T2 (at constant volume)
P1 = P
T1 =T
P2 = ?
T2 = 4 T
So therefore;
P2 = P1T1/ T2
P2 = P T/ 4 T
P2 = 1/4 P
The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.
Answer:
Not exactly But you can take the slope of the curved portion and the slope of the flatline.
It wont do you much good since your working for absorbance but if you ever see something like a temperature change you can use the slope(s) to find freezing points/melting
Explanation:
If you need to submit a slope you could use a best fit which is just point to point or you could break it up like i mentioned
