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Mamont248 [21]
3 years ago
12

What are isotopes? how are they different from each other?

Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0
Isotopes are two or more of the same type of element. They are different because they all have a different relative atomic mass.
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A nitric acid solution containing 71.0% HNO3 (by mass) is available in a laboratory. How many moles of HNO3 are present in 1.98
lora16 [44]

Answer:   e. none of these

Explanation:

Mass percent is the ratio of mass of solute dissolved to the mass of solution in terms of percentage.

Thus 71.0% HNO_3 means 71.0 g of HNO_3 is present in 100 g of solution  

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of HNO_3  = 71.0 g

Molar mass of  HNO_3 = 63.01 g/mol

Putting in the values we get:

\text{Number of moles}=\frac{71.0g}{63.01g/mol}=1.13moles

Thus there are 1.13 moles of HNO_3

6 0
3 years ago
HELP PLEASE ASAP!!!!!
Oksana_A [137]

Answer:

I think it's c

Explanation:

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3 years ago
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What is the volume (ML) of water
Dovator [93]

Answer:

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One milliliter (1 mL) of water has a volume of 1 cubic centimeter (1cm3).

6 0
2 years ago
The representatives anticipated that the Declaration of Rights and Grievances would lead to:
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a war with Britain

the declaration of rights and grievances was written as protest to the Stamp Act, which was in 1765

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3 years ago
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5. A gas has a pressure of 310 kPa at 237 degrees C.<br>What will its pressure be at 23 degrees C?)​
slavikrds [6]

Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
  • T1= 237 C= 510 K (being 0 C= 273 K)
  • P2= ?
  • T2= 23 C= 296 K

Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

5 0
3 years ago
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