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mixer [17]
3 years ago
7

Your science teacher removed the gas from a birthday balloon. They discovered that the gas is made of the element helium. Inside

that atom is:
A. A new substance
B. Protons, neutrons and electrons
C. A different element
D. All of the above
Chemistry
2 answers:
slega [8]3 years ago
8 0
The answer would be “B” because a substance and element represent a structure larger than a single atom. Please mark as Brainliest answer!
soldier1979 [14.2K]3 years ago
4 0
D is the answer I think
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At 25 ∘ C , the equilibrium partial pressures for the reaction 3 A ( g ) + 4 B ( g ) − ⇀ ↽ − 2 C ( g ) + 3 D ( g ) were found to
VMariaS [17]

<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ

<u>Explanation:</u>

For the given chemical equation:

3A(g)+4B(g)\rightleftharpoons 2C(g)+3D(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_C)^2\times (p_D)^3}{(p_A)^3\times (p_B)^4}

We are given:

(p_A)_{eq}=5.70atm\\(p_B)_{eq}=4.00atm\\(p_C)_{eq}=4.22atm\\(p_D)_{eq}=5.52atm

Putting values in above expression, we get:

K_p=\frac{(4.22)^2\times (5.52)^3}{(5.70)^3\times (4.00)^4}\\\\K_p=0.0632

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314 J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = 0.0632

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.0632)\\\\\Delta G^o=6841.7J=6.84kJ

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ

6 0
4 years ago
Why are things weightless on the International Space Station?
alexandr402 [8]
There is no gravity and gravity pulls things down
3 0
3 years ago
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The reaction          3 BrO- (aq) --&gt; BrO3- (aq) + 2 Br - (aq) in basic solution is second order in BrO-(aq) with a rate cons
Phoenix [80]

Answer:

0.124 M

Explanation:

The reaction obeys second-order kinetics:

r = k[BrO^-]^2

According to the integrated second-order rate law, we may rewrite the rate law in terms of:

\dfrac{1}{[BrO^-]_t} = kt + \dfrac{1}{[BrO^-]_o}

Here:

k is a rate constant,

[BrO^-]_t is the molarity of the reactant at time t,

[BrO^-]_o is the initial molarity of the reactant.

Converting the time into seconds (since the rate constant has seconds in its units), we obtain:

t = 1.00 min = 60.0 s

Rearranging the integrated equation for the amount at time t:

[BrO^-]_t = \dfrac{1}{kt + \dfrac{1}{[BrO^-]_o}}

We may now substitute the data:

[BrO^-]_t = \dfrac{1}{0.056 M^{-1}s^{-1}\cdot 60.0 s + \dfrac{1}{0.212 M}} = 0.124 M

7 0
3 years ago
How many total valence electrons are found in the following molecules: CO3
photoshop1234 [79]

Answer:

The Carbonate (CO2−3) Ion

Unlike O3, though, the actual structure of CO32− is an average of three resonance structures. 2. Carbon has 4 valence electrons, each oxygen has 6 valence electrons, and there are 2 more for the −2 charge. This gives 4 + (3 × 6) + 2 = 24 valence electrons

Explanation:

7 0
3 years ago
Gordon throws a baseball into the air. It rises, stops when it reaches its greatest height, and then falls back to the ground. A
Ivahew [28]

That would be when the baseball is rising. The energy from the throw is kinetic energy.

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3 years ago
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