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Ksenya-84 [330]
2 years ago
15

A mixture of propane and butane is burned with pure oxygen. The combustion products contain 46.7 mole% H2O. After all the water

is removed from the products, the residual gas contains 69.0 mole% CO2 and the balance O2 a. What is the mole percent of propane in the fuel?
Chemistry
1 answer:
wlad13 [49]2 years ago
5 0

Answer:

28%

Explanation:

Basically, all o did was write the equations, balance it and solve for them. Also, at the place I stared, I used simultaneous equation to solve it. Multiplying by 8 and also 3.

It's a pretty straightforward question.

At the final step that's missing, I Did

(y)C3H8 = 2.8 / ( 2.8 + 7.1)

(y)C3H8 = 0.28

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<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

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We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

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Density of the gold bar = 193.0 g ÷ 10 cm³

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