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xenn [34]
2 years ago
8

Identical wire loops are dipped into Liquid X and Liquid Y, so that a film of liquid forms across the loops (like the bubble sol

ution on a child's bubble blowing wand). The width of each loop is increased slowly and the forces FX and FY needed to make the loops 5% wider are measured.
a. FX will be greater than F Y
b. FX will be less than FY
c. FX will be equal to FY
d. It's impossible to predict whether F X or FY will be greater without more information.
Chemistry
1 answer:
muminat2 years ago
6 0

Answer:

a.

Explanation:

Assuming that Liquid X is considered to possess a greater viscosity as well as higher surface tension than liquid Y. Then, liquid X will tend to harbour more pressure inside the liquid.

In addition to that, the greater the surface tension, the greater the force required to expand the liquid's surface area.

This in turn makes the force required to make the loop 5% wider to be greater in FX rather than FY.

Thus, option a is the correct answer.

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The density of the rectangular block in g/mL is 7.0.

<u>Given the following data:</u>

  • Mass of block = 22.8 gra1.94 kg
  • Length of block = 3.21 cm
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  • Height of block = 1.84 in.

To find the density of the block in g/mL:

First of all, we would determine the volume of the rectangular block by using the following formula:

Volume = length × width × height

<u>Conversion:</u>

1 in = 2.54 cm​

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Cross-multiplying, we have:

X = 2.54(5.83)\\\\X = 14.81 \; cm

Volume = 3.21 × 5.83 × 14.81

Volume = 277.16 cubic centimeters.

<u>Note</u>: Milliliter (mL) is the same as cubic centimeters.

1000 grams = 1 kg

Y grams = 1.94 kg

Cross-multiplying, we have:

Y = 1940 grams

Now, we can find the density:

Density = \frac{Mass}{Volume}\\\\Density = \frac{1940}{277.16}

<em>Density </em><em>= 7</em><em>.0 g/mL</em>

Therefore, the density of the rectangular block in g/mL is 7.0.

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