Total volume = 80 mL + 20 mL = 100 mL = 0.10 L.
NaOH + HCl ----> NaCl + H2O.
0.08 L * 2.00 mol NaOH/L = 0.16 moles NaOH.
0.02 L * 4.00 mol HCl/L = 0.08 moles HCl.
0.16 - 0.08 = 0.08. There are 0.08 moles NaOH XS.
0.08 moles NaOH produces 0.08 moles OH-.
Concentration OH- = 0.08 moles / 0.10 L = 0.8 M.
Sodium sulfate is the answer you are looking for
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance

2) Determine the limitting reagent

∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation:
Answer:
8.3ml
Explanation:
to get volume u have to divide 25g over the density, i rounded to the nearest tenth, if you don't want to then write out the full number with all the decimals