18.8 mol= mass of He X atomic mass
18.8 mol= mass of He X 4 g mol^-1
mass of He= (18.8 X 4)g = 75.2 g
Answer:
Populations for whom water is a limiting factor will increase in size.
Explanation:
V) the amount of sugar in the solution
C) whether the sugar is stirred
V) the temperature of the solution
C) the type of solute added
C) the type of solvent used
NP.
At STP conditions the volume of 1 mol of any ideal gas will be 22.4L
0.500 mol C3H3 x 22.4L / 1 mol = 11.2 L
