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vazorg [7]
3 years ago
14

Two parallel plates have a potential difference between them. The distance between the plates is halved, but the electric field

between them remains constant. How did the potential difference change?
A. Potential difference was halved.


B. Potential difference did not change.


C. Potential difference was doubled.


D. Potential difference was quadrupled.
Physics
1 answer:
zhuklara [117]3 years ago
8 0

For a set of very long (essentially infinitely long) charged parallel plates, the electric field between them is constant, and the electric field is given by

E = ΔV/d

ΔV is the potential difference between the plates and d is the distance of their separation.

If d is halved but E stays constant, then by the relationship above, ΔV must also have been halved.

A. Potential difference was halved.

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An ideal gas is compressed at constant pressure p=1500 Pa from a volume Vi=0.4 m3 to Vf=0.25 m3. At the same time, heat is trans
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To solve this problem we will apply the first law of thermodynamics and we will make a balance between the heat transferred, its internal energy and the total work. Recall that for gases the definition of work can be expressed in terms of its pressure and volume. Let's start

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Here,

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But internal energy is unchanged, then

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4 years ago
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C

Explanation:

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Answer:

0.0110284391534\ N

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Force of gravity is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 2000\times 2.1}{(5.04\times 10^{-3})^2}\\\Rightarrow F=0.0110284391534\ N

The gravitational force is 0.0110284391534\ N

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