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vazorg [7]
3 years ago
14

Two parallel plates have a potential difference between them. The distance between the plates is halved, but the electric field

between them remains constant. How did the potential difference change?
A. Potential difference was halved.


B. Potential difference did not change.


C. Potential difference was doubled.


D. Potential difference was quadrupled.
Physics
1 answer:
zhuklara [117]3 years ago
8 0

For a set of very long (essentially infinitely long) charged parallel plates, the electric field between them is constant, and the electric field is given by

E = ΔV/d

ΔV is the potential difference between the plates and d is the distance of their separation.

If d is halved but E stays constant, then by the relationship above, ΔV must also have been halved.

A. Potential difference was halved.

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The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours

<h3>What is time?</h3>

Time is the measurement of a past, present, or future event. The S.I unit of time is seconds (s)

To get the time that was saved on the 8.6-mile trip, we use the formula below.

Formula:

  • Ts = (d/v₁)-(d/v₂)................. Equation 1.

Where:

  • Ts = Time saved on the trip
  • d = distance covered during the trip
  • v₁ = Initial legal speed limit
  • v₂ = final/current legal speed limit.

From the question,

Given:

  • d = 86.0 mile
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  • v₂ = 75.0 mi/h

Substitute these values into equation 1

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Hence, The amount of time saved on the 86.0 mile trip from Tulsa entrance to Oklahoma City is 0.42 hours.

Learn more about time here: brainly.com/question/13893070

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A ball is launched straight up with initial speed of 30.0 m/s. What is the ball's velocity when it comes back to its original po
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Explanation:

I looked it up

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