What is happening at the atomic level to give rise to the observed energy?

1 answer:

6 0

Here is the answer. What is happening at the atomic level to give rise to the observed energy is that the atomic level is affected by the movement of electrons so as to give rise to the observed energy. Hope this answers your question. Have a great day!

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A circuit consists of a 9.0 mH inductor coil, a 230 Ω resistor, a 12.0 V ideal battery, and an open switch-all connected in seri

Nutka1998 [239]

Answer:

Explanation:

This is the case of L-R charging circuit , for which the formula is as follows

i = i₀ ( 1 - $e^{\frac{-t}{\tau}$ )

Differentiating the equation on both sides

di / dt = i₀ / τ x $e^\frac{-t}{\tau}$

i is current at time t , i₀ is maximum current , τ is time constant which is equal to L / R where L is inductance and R is resistance of the circuit .

τ = L / R = 9 x 10⁻³ / 230

= 39 x 10⁻⁶ s

i₀ = 12 / 230 = 52.17 x 10⁻³

di / dt (at t is zero) = 52.17 x 10⁻³ / 39 x 10⁻⁶

= 1.33 x 10³ A / s

Time to reach 85 % of steady state or i₀

.85 = $1 - e^\frac{t}{\tau}$

$e^\frac{-t}{\tau}$ = .15

t / τ = ln .15

t = 74 μs

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Identify two simple machines in this compound machine. A. screw, lever B. screw, incline plane C. double pulley D. lever, pulley

seropon [69]

It's A, the Screw leaver

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What is the wavelength (in nm) of a photon emitted during transition from the n = 3 state to the n = 1 state in the H atom?

Mkey [24]

Answer:

$\lambda=103\ nm$

Explanation:

$E_n=-2.179\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.179\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.179\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$