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nlexa [21]
3 years ago
14

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

l velicity of +5800m/s, while Rocket B has an initial velocity of +8600m/s. After a time t both rockets are again side by side, the displacement of each being zero. The acceleration of rocket A is -15m/s^2. What is the acceleration of rocket B?
Physics
1 answer:
earnstyle [38]3 years ago
6 0

Answer:

The acceleration of rocket B is -22.24 m/s²

Explanation:

Two rockets are flying in the same direction and are side by side at the

instant their retrorockets fire

That means they started from the same point at the same time

Rocket A has an initial velocity of  5800 m/s

Rocket B has an initial velocity of 8600 m/s

After a time t both rockets are again side by side, the displacement of

each being zero

That means they are in the same position again → s = 0

The acceleration of rocket A is  -15 m/s²

We need to find the acceleration for rocket B

We can find the time from the information of rocket A by using the

rule → s = u t + \frac{1}{2} a t²

where s is the displacement, u is the initial velocity, a is the

acceleration, and t is the time

→ s = 0 , u = 5800 m/s , a = -15 m/s²

Substitute these values in the rule

→ 0 = 5800 t + \frac{1}{2} (-15) t²

→ 0 = 5800 t - 7.5 t²

Add 7.5 t² for both sides

→ 7.5 t² = 5800 t

Divide both sides by 7.5 t

→ t = 773.3 s

The time for the both rocket to have displacement zero is 773.3 s

Now we can find the acceleration of the rocket B by using the same

rule above

→ u = 8600 m/s , t = 773.3 , s = 0

→ 0 = (8600)(773.3) + \frac{1}{2} a (773.3)²

→ 0 = 6650380 + 298996.445 a

Subtract 6650380 from both sides

→ -6650380 = 298996.445 a

Divide both sides by 298996.445

→ a = -22.24 m/s²

<em>The acceleration of rocket B is -22.24 m/s²</em>

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Answer:

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Explanation:

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Formula used for the radius of the n^{th} orbit will be,

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E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number

Here: Z = 1 (hydrogen atom)

Energy of the first orbit in H atom .

E_1=-13.6\times \frac{Z^2}{1^2} eV=-13.6 eV

Energy of the second orbit in H atom .

E_2=-13.6\times \frac{Z^2}{(2)^2} eV=-3.40 eV

Energy of the third orbit in H atom .

E_3=-13.6\times \frac{Z^2}{(9)^2} eV=-1.51 eV

Energy of the fifth orbit in H atom .

E_5=-13.6\times \frac{Z^2}{(2)^2} eV=-0.544 eV

Energy of the sixth orbit in H atom .

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Energy of the seventh orbit in H atom .

E_7=-13.6\times \frac{Z^2}{(2)^2} eV=-278 eV

During an absorption of energy electron jumps from lower state to higher state.So,  absorption will take place in :

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E=(-1.51 eV) -(-3.40 eV)=1.89 eV

Energy absorbed when: n = 5 → n = 6

E'=E_6-E_5

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1.89 eV > 0.166 eV

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3 years ago
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bagirrra123 [75]

Answer:

(1) An object that’s negatively charged has more electrons than protons.

(2) An object that’s positively charged has fewer electrons than protons.

(3) An object that’s not charged has the same number of electrons than protons.

Explanation :

Objects have three subatomic particles that are Electrons, protons, and neutrons.

Protons and neutrons are found in the nucleus and electrons rotate or move outside the nucleus. Naturally, protons are positively charged, neutrons have no charge, and electrons are negatively charged.

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8 0
3 years ago
1. The illuminance on a surface is 6 lux and the surface is 4 meters from the light source. What is the intensity of the source?
Crank

<u>Answer</u>

1) A. 96 Candelas

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3) C. 5 meters


<u>Explanation</u>

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Lv = Ev × r²

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= 96 Candelabra

Q2

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A. Both of these types of lenses have the ability to produce upright images.

Q3

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square radius = Luminous intensity/ illuminance

r² = 100/4

= 25

r = √25

= 5 m




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3 years ago
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Answer:

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