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Lisa [10]
3 years ago
6

Work is required to lift a barbell. How many times more work is required to lift the barbell three times as high

Physics
1 answer:
bixtya [17]3 years ago
7 0
The work times 3 .
N.B: Work = Force x Distance
and in here the distance increased to 3.
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An inclined plane reduces the effort force by _____.
xz_007 [3.2K]
"increasing the distance through which the force is applied" 
3 0
3 years ago
Read 2 more answers
Henrietta is going off to her physics class, jogging down the sidewalk at a speed of 4.15 m/s . Her husband Bruce suddenly reali
aleksandr82 [10.1K]

Answer:

a 15.22 m/s

b 45.65 m

Explanation:

Using the same formula,

x = vt, where

x is now 45.65, and

t is 3 s, then

45.65 = 3v

v = 45.65/3

v = 15.22 m/s

See the attachment for the part b. We used the distance gotten in part B, to find question A

5 0
3 years ago
An object slides on a level surface in the +x direction. It slows and comes to a stop with a constant acceleration of -2.45 m/s2
Stolb23 [73]

Answer:

uk = 0.25

Explanation:

Given:-

- An object comes to stop with acceleration, a = -2.45 m/s^2

Find:-

What is the coefficient of kinetic friction between the object and the floor?

Solution:-

- Assuming the object has mass (m) that slides over a rough surface with coefficient of kinetic friction (uk). There is only Frictional force (Ff) acting in the horizontal axis on the object opposing the motion (-x direction).

- We will apply equilibrium equation on the object in vertical direction.

                               N - m*g = 0

                               N = m*g

Where,  N : Contact force exerted by the surface on the floor

             g : Gravitational acceleration constant = 9.81 m/s^2

- Now apply Newton's second law of motion in the horizontal ( x-direction ):

                             - Ff = m*a

- The frictional force is related to contact force (N) by the following expression:

                              Ff = uk*N

- Substitute the 1st and 3rd expressions in the 2nd equation:

                             uk*m*g = -m*a

                             uk = a / g

- Plug in the values and solve for uk:

                             uk = - (-2.45) / 9.81

                             uk = 0.25        

8 0
3 years ago
An emf is induced by rotating a 1060 turn, 20.0 cm diameter coil in the Earth's 5.25 ✕ 10−5 T magnetic field. What average emf (
lara31 [8.8K]

Answer:

The average emf induced in the coil is 175 mV

Explanation:

Given;

number of turns of the coil, N = 1060 turns

diameter of the coil, d = 20.0 cm = 0.2 m

magnitude of the magnetic field,  B = 5.25 x 10⁻⁵ T

duration of change in field, t = 10 ms = 10 x 10⁻³ s

The average emf induced in the coil is given by;

E = N\frac{\delta \phi}{dt} \\\\E = N\frac{\delta B}{\delta t}A

where;

A is the area of the coil

A = πr²

r is the radius of the coil = 0.2 /2 = 0.1 m

A = π(0.1)² = 0.03142 m²

E = \frac{NBA}{t} \\\\E = \frac{1060*5.25*10^{-5}*0.03142}{10*10^{-3}} \\\\E = 0.175 \ V\\\\E = 175 \ mV

Therefore, the average emf induced in the coil is 175 mV

3 0
3 years ago
A rock falls of a cliff and hits the ground after 3 seconds. What is it’s velocity right before it hits the ground? A.0.31 m/s B
LekaFEV [45]
Hopefully this will help you.

8 0
3 years ago
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