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Yanka [14]
4 years ago
11

By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows. The pulley can be tre

ated as a uniform solid cylindrical disk. The downward acceleration of the 44.0-kg block is observed to be exactly 1/4 the acceleration due to gravity. Noting that the tension in the rope is not the same on each side of the pulley, find the mass of the pulley.
Physics
1 answer:
tankabanditka [31]4 years ago
5 0

Answer:

Mass of the pull is 77 kg

Explanation:

Here we have for

Since  the rope moves along with pulley, we have

For the first block we have

T₁ - m₁g = -m₁a = -m₁g/4

T₁ =  3/4(m₁g) = 323.4 N

Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have

T₂ - m₂g = m₂a = m₂g/4

T₂ =  5/4(m₂g) = 134.75 N

T₂r - T₁r = I·∝ = 0.5·M·r²(-α/r)

∴ M = -\frac{2}{a} (T_2-T_1)

M = -\frac{2}{2.45} (134.75-323.4) = 77 \, kg

Mass of the pull = 77 kg.

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Calculate the calories lost when 95 g of water cools from 45 ∘C to 29 ∘C. Express your answer to two significant figures and inc
lubasha [3.4K]

Answer:

1,520.00 calories

Explanation:

Water molecules are linked by hydrogen bonds that require a lot of heat (energy) to break, which is released when the temperature drops. That energy is called specific heat or thermal capacity (ĉ) when it is enough to change the temperature of 1g of the substance (in this case water) by 1°C. Water ĉ equals 1 cal/(g.°C).

Given that ĉ = Q / (m.ΔT),

where Q= calories transferred between the system and its environment or another system (unity: calorie or cal) (what we are trying to find out),

m= mass of the substance (unity: grams or g), and

ΔT= difference of temperature (unity: Celsius degrees or °C); and

m= 95g and ΔT= 16°C:

Q= 1 cal/(g.°C).95g.16°C =<u> 1,520.00 cal </u>

8 0
4 years ago
The magnitude of the velocity of a projectile when it is at its maximum height above ground level is 14 m/s. (a) What is the mag
Alecsey [184]

When the projectile is at its maximum height above ground, it's at the point
of changing from rising to falling.  At that exact point, its vertical speed is zero,
so the 14 m/s must be all horizontal velocity.  That's not going to change.

Since we need to consider changes in vertical speed now, we need to make
some assumption about where this is all happening, so that we know the
acceleration of gravity.  I'll assume that it's all happening on or near the Earth,
and the acceleration of gravity is 9.8 m/s².

I'm also going to neglect air resistance.

a). 1.2 sec before it reaches its maximum height, the projectile is rising
at a vertical speed of (1.2 x 9.8) = 11.76 m/s. 
The magnitude of its velocity is

the square root of (14² + 11.76²) = 18.28 m/s, directed about 40° above horizontal.

b).  1.2 sec after it reaches its maximum height, the projectile is falling
at a vertical speed of (1.2 x 9.8) = 11.76 m/s. 
The magnitude of its velocity is

the square root of (14² + 11.76²) = 18.28 m/s, directed about 40° below horizontal.

===========================

In 1.2 second before or after zero vertical speed, an object in free fall moves

         (1/2) (g) (t²) = (4.9) (1.2²) = 7.06 meters .

c). & d).
1.2 seconds before it reaches maximum height, the projectile is located at

           x = -14 m
           y = -7.06 m

e). & f).
1.2 seconds after it reaches maximum height, the projectile is located at

           x = +14 m
           y = -7.06 m .


I hope you recognize that 6 answers, plus a little bit of explanation,
all for 5 points, ain't too shabby.  You made out well.

5 0
3 years ago
A car is traveling at a speed of 50 km/hr. The positive y-axis is north and the positive x-axis is east. Resolve the car's veloc
hjlf
We need to draw a coordinates. the east and south should be the north vector for horizontal line 50 KM in distance is zero. the south is a negative. the south east and north west we should draw the 45 degrees angle in the approprate quadrant and then use the 1-1-sqrt(2) have a relationship in 45-45-90 triangles to resolve the N/S, E/W components.

hope this help
6 0
3 years ago
The half life of a species that undergoes zero order kinetics is ____ and the rate constant has units of ____.
-BARSIC- [3]
The reaction of the half-life is a description of the needed time for the reactant to deplete.In the first order reactions formula, k is considered as the first order rate constant whose unit is denoted as 1/s. Hope this helps.
6 0
4 years ago
How do we find the average force in physics?​
svlad2 [7]
Force is equal to mass multiplied by acceleration. Hope this helps!
8 0
3 years ago
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