Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s2, what is the radius of the circle?
0.60 m
1.2 m
0.36 m
0.84 m

Answer 1

By definition, the centripetal acceleration is given by:

$a = \frac{v^2}{r}$

Where,

v: tangential speed

r: radius of the circular path

Clearing the radio we have:

$r = \frac{v^2}{a}$

Substituting values we have:

$r =\frac{0.51 ^ 2}{0.43}\\r = 0.6 m$

Therefore, the radius of the circular path is equal to 0.60 meters.

Answer:

The radius of the circle is:

0.60 m

option1

Answer 2

I googled it and I think the answer is 0.60m

good luck!