All categories

3 years ago

• How does wind shape Earth’s surface?

Physics

1 answer:

ehidna [41]3 years ago

6 0

Lamina and turbulent flow

Explanation:

mentioning about lamina and turbulent flow we could say that both form in different period of time

You might be interested in

Які лампочки у схемі з'єднані<br> паралельно?

alekssr [168]

Answer:

I don't understand please interpret

5 0

3 years ago

Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac

alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = $47\times 10^{-9}\ C/m^2$

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

$E=\dfrac{\sigma}{2\epsilon_0}$

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

$E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}$

Now, plug in $47\times 10^{-9}\ C/m^2$ for 'σ' and $8.85\times 10^{-12}\ F/m$ for $\epsilon_0$ and solve for the electric field. This gives,

$E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C$

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0

3 years ago

A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. W

DENIUS [597]

Answer

given,

mass of the drop, m = 0.0014 g

speed of the drop, u = 8.1 m/s

a) Change in momentum is equal to impulse

final velocity of the drop, v = 0 m/s

J = m ( v - u )

J = 0.0014 x 10⁻³ x ( 0 - 8.1 )

J = -1.134 x 10⁻⁵ kg.m/s

impulse of the roof = - J = 1.134 x 10⁻⁵ kg.m/s

b) time, t = 0.37 m s

impact of force = ?

we know

J = F x t

1.134 x 10⁻⁵ = F x 0.37 x 10⁻³

F = 0.031 N

the magnitude of the force of the impact is equal to F = 0.031 N

5 0

3 years ago

A boat is heading across a river at a velocity of 25 mph. The river is flowing downstream at 10 mph. What is the actual velocity

AnnyKZ [126]

Principle: Pythagorean theorem

Given:
Let a = boat velocity = 25 miles per hour
b = river velocity = 10 miles per hour

Required: c = actual velocity

Solution:

c^2 = a^2 + b^2
c^2 = (25)^2 + (10)^2
c^2 = 725
(c^2)^0.5 = (725)^0.5
c = 26.93 miles per hour

<em>ANSWER: Actual boat velocity is 26.93 miles per hour</em>

8 0

3 years ago

Q|C A string with linear density 0.500 g/m is held under tension 20.0 N. As a transverse sinusoidal wave propagates on the strin

julia-pushkina [17]

A string with linear density 0.500 g/m.

Tension 20.0 N.

The maximum speed $v_{y, max}$