Given:-

To graph and explain.
So the graph of the given function is,
An integral in mathematics is either a numerical value equal to the area under the graph of a function for some interval or a new function, the derivative of which is the original function.
Answer:
2e+13
Step-by-step explanation:
Answer:
is the value of x. Step-by-step explanation: We have been given the two terms which are equivalent means they have equal value: and . So, by the given information: we have to solve for x: Firstly, we will cross multiply so, we will get: After simplification we will get the final result is the value of x.
Step-by-step explanation:
Answer:
<h2>

</h2>
Step-by-step explanation:

To find ( f - g)(x) , subtract g(x) from f(x)
That's

Since they have a common denominator that's 3x we can subtract them directly
That's

We have the final answer as
<h3>

</h3>
Hope this helps you
Answer:
The area is growing at a rate of 
Step-by-step explanation:
<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>
We identify that the info given on the increasing rate of the circle's radius is 3
and we identify such as the following differential rate:

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find
.
So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

We now apply the derivative operator with respect to time (
) to this equation, and use chain rule as we find the quadratic form of the radius:
![\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5BA%3D%5Cpi%5C%2Cr%5E2%5D%5C%5C%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%5Cpi%5C%2C%2A2%2Ar%2A%5Cfrac%7Bdr%7D%7Bdt%7D)
Now we replace the known values of the rate at which the radius is growing (
), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

which we can round to one decimal place as:
