The two Old Testament chapters filled with prophecies concerning Jesus Christ are:
Isaiah 9:6: Here, Isaiah was said to have prophesies that Jesus Christ will be born and he will come as a baby; Jesus was known to be called by several names here such as the Prince of peace.
Micah 5:2L Here, Micah was said to have prophesies that Jesus will be born in a town that is called Bethlehem.
<h3>What is the message of Isaiah 9?</h3>
The kind of message is one that can be seen mostly in Isaiah 9:1-7. Isaiah was known to be a prophet who was said to have announced that there is what we see presently gloom and distress and there a time will arise or come to pass when there will be happiness, joy and salvation.
The reason for the above is because a child will be born who will be the savior of the whole world and through him, the Rod of the Oppressor will be destroyed.
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Answer:
t₁ - t₂ = 0.0011 s
Explanation:
given,
y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
now,
y m = 6 mm ω = 600 rad/s
y₁ = + 2.0 mm y₂ = -2 .0 mm
now,
2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
so,
kx + (600 rad/s)t₁ + Φ = 
......(1)
we have multiplied with π/180 to convert angle into radians
kx + (600 rad/s)t₂ + Φ = 
......(2)
subtracting both the equation (1)-(2)
600(t₁-t₂) = 
now,
t₁ - t₂ = 0.0011 s
time does any given point on the string take to move between displacements is equal to 0.0011 s
D. Genetic variation increases the likelihood of an allele being present that is best suited for the environment.
Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?
Answer:
0.133 kg
Explanation:
Applying the law of conservation of momentum,
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')................... Equation 1
Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.
From the question,
Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s
Substitute these values into equation 2
(0.8*15)+(m'*20) = 10(0.8+m')
Solve for m'
12-20m' = 8+10m'
-20m'-10m' = 8-12
-30m' = -4
m' = -4/-30
m' = 0.133 kg
The 4ohm resistor is not parallel to any devices, so the current through it is the same as the total current through the circuit.
Apply I = V/R
I = total current, V = battery voltage, R = total resistance
Calculate the total resistance R of the circuit first.
R will be the sum of the 4ohm resistor and the resistance of the 5&9ohm parallel resistors. To find the resistance of the pair, you apply the “sum of inverses” rule:
R = 1/(1/5 + 1/9) = 3.21ohm
Now add the 4ohm resistor:
R = 3.21 + 4 = 7.21ohm
Now let’s calculate I = V/R:
Given values:
V = 6.0V
R = 7.21ohm
Plug in and solve for I:
I = 6.0/7.21
I = 0.83A
