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2 years ago

ESSAY: PROPHECY

Physics

1 answer:

kogti [31]2 years ago

5 0

The two Old Testament chapters filled with prophecies concerning Jesus Christ are:

Isaiah 9:6: Here, Isaiah was said to have prophesies that Jesus Christ will be born and he will come as a baby; Jesus was known to be called by several names here such as the Prince of peace.

Micah 5:2L Here, Micah was said to have prophesies that Jesus will be born in a town that is called Bethlehem.

<h3>What is the message of Isaiah 9?</h3>

The kind of message is one that can be seen mostly in Isaiah 9:1-7. Isaiah was known to be a prophet who was said to have announced that there is what we see presently gloom and distress and there a time will arise or come to pass when there will be happiness, joy and salvation.

The reason for the above is because a child will be born who will be the savior of the whole world and through him, the Rod of the Oppressor will be destroyed.

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A plane travels 1743 KM in 2 hours 30 minutes. How fast was the plane traveling?

Advocard [28]

Answer:

$v=697.2km/h$

Explanation:

Hello.

In this case, since the velocity is computed via the division of the distance traveled by the elapsed time:

$V=\frac{d}{t}$

The distance is clearly 1743 km and the time is:

$t=2h+30min*\frac{1h}{60min} =2.5h$

Thus, the velocity turns out:

$v=\frac{1743km}{2.5h}\\ \\v=697.2km/h$

Which is a typical velocity for a plane to allow it be stable when flying.

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3 years ago

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lutik1710 [3]

Answer: I think, the number of oscillations in a given period of time.

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3 years ago

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The free-body diagram of a crate is shown. A free body diagram with 4 force vectors. The first vector is pointing downward, labe

satela [25.4K]

The net force acting on the crate is determined as 176 N to the left.

<h3>Net force acting on the crate</h3>

The net force acting on the crate is calculated as follows;

∑F = F1 + F2 + F3 + F4

F(net) = -440y + 176x + 440y - 352x

F(net) = -176 x

The resultant force is pointing in negative x direction.

Thus, the net force acting on the crate is determined as 176 N to the left.

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2 years ago

28.25 mL, three signicant digits

Mazyrski [523]

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3 years ago

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14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards

quester [9]

The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

500N = 90kg x a

a = 5.55 m/s².

Now, the weight if the lineman is 120kg, the force applied by him is 500N.

So, from the formula, his acceleration A will be,

500N = 120Kg x A

A = 4.16 m/s².

both of them will have acceleration in the same direction,

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