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3 years ago

The name of the Sl unit for force is the ___? A. Joule B. Newton C.Watt

Physics

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

the name of the SI unit for force is the newton

Sergio039 [100]3 years ago

7 0

Answer:

newton

Explanation:

don't have explanation

but I know this is the answer

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Two particles with masses 2m and 9m are moving toward each other along the x axis with the same initial speeds vi. Particle 2m i

s2008m [1.1K]

Answer:

The final speed for the mass 2m is $v_{2y}=-1,51\ v_{i}$ and the final speed for the mass 9m is $v_{1f} =0,85\ v_{i}$ .

The angle at which the particle 9m is scattered is $\theta = -66,68^{o}$ with respect to the - y axis.

Explanation:

In an elastic collision the total linear momentum and the total kinetic energy is conserved.

<u>Conservation of linear momentum:</u>

Because the linear momentum is a vector quantity we consider the conservation of the components of momentum in the x and y axis.

The subindex 1 will refer to the particle 9m and the subindex 2 will refer to the particle 2m

$\vec{p}=m\vec{v}$

$p_{xi} =p_{xf}$

In the x axis before the collision we have

$p_{xi}=9m\ v_{i} - 2m\ v_{i}$

and after the collision we have that

$p_{xf} =9m\ v_{1x}$

In the y axis before the collision $p_{yi} =0$

after the collision we have that

$p_{yf} =9m\ v_{1y} - 2m\ v_{2y}$

$p_{xi} =p_{xf} \\7m\ v_{i} =9m\ v_{1x}\Rightarrow v_{1x} =\frac{7}{9}\ v_{i}$

then

$p_{yi} =p_{yf} \\0=9m\ v_{1y} -2m\ v_{2y} \\v_{1y}=\frac{2}{9} \ v_{2y}$

<u>Conservation of kinetic energy:</u>

$\frac{1}{2}\ 9m\ v_{i} ^{2} +\frac{1}{2}\ 2m\ v_{i} ^{2}=\frac{1}{2}\ 9m\ v_{1f} ^{2} +\frac{1}{2}\ 2m\ v_{2f} ^{2}$

$\frac{11}{2}\ m\ v_{i} ^{2} =\frac{1}{2} \ 9m\ [(\frac{7}{9}) ^{2}\ v_{i} ^{2}+ (\frac{2}{9}) ^{2}\ v_{2y} ^{2}]+ m\ v_{2y} ^{2}$

Putting in one side of the equation each speed we get

$\frac{25}{9}\ m\ v_{i} ^{2} =\frac{11}{9}\ m\ v_{2y} ^{2}\\v_{2y} =-1,51\ v_{i}$

We know that the particle 2m travels in the -y axis because it was stated in the question.

Now we can get the y component of the speed of the 9m particle:

$v_{1y} =\frac{2}{9}\ v_{2y} \\v_{1y} =-0,335\ v_{i}$

the magnitude of the final speed of the particle 9m is

$v_{1f} =\sqrt{v_{1x} ^{2}+v_{1y} ^{2} }$

$v_{1f} =\sqrt{(\frac{7}{9}) ^{2}\ v_{i} ^{2}+(-0,335)^{2}\ v_{i} ^{2} }\Rightarrow \ v_{1f} =0,85\ v_{i}$

The tangent that the speed of the particle 9m makes with the -y axis is

$tan(\theta)=\frac{v_{1x} }{v_{1y}} =-2,321 \Rightarrow\theta=-66,68^{o}$

As a vector the speed of the particle 9m is:

$\vec{v_{1f} }=\frac{7}{9} v_{i} \hat{x}-0,335\ v_{i}\ \hat{y}$

As a vector the speed of the particle 2m is:

$\vec{v_{2f} }=-1,51\ v_{i}\ \hat{y}$

8 0

3 years ago

An engineer is investigating potential energy with two

miv72 [106K]

Answer:

Since they move in the same direction, share the same magnetic qualities, and move one unit identically
We can safely say its D

4 0

3 years ago

Read 2 more answers

A boy drops a 0.10 kg stone down a 150 m well and listens for the echo. The air temperature is 20°C. How long after the stone is

S_A_V [24]

Use formula for Echo which is Velocity=2(Distance)/time so 343=2(150)/T 343T=300..T=300/343=0.9 seconds

4 0

3 years ago

An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation

Scrat [10]

What the equation given?

x(t)=Acos $\omega$ t

Maximum velocity occurs at the equilibrium position

Now

x(0)=Acos0[/tex]
x(0)=A

Now

As we know the formula

$\\ \rm\rightarrowtail V_max=A\omega$

These expressions can be used

3 0

2 years ago

El aspa de un ventilador de 0.30 m de diametro gira 1200 rev/min. calcule la rapidez tangencial.

Keith_Richards [23]

Answer:

v = 18.84 m/s

Explanation:

Let the question says,"The blade of a 0.30 m diameter fan rotates 1200 rev / min. calculate the tangential speed."

It is given that,

Diameter of a blade of fan is 0.3 m

Angular velocity of the fan is 1200 rev/min or 125.66 rad/s

We need to find the tangential speed of the fan. The relation is given by :

$v=r\omega$

r is radius of fan

$v=0.15\times 125.66 \\\\v=18.84\ m/s$

So, the tangential velocity is 18.84 m/s.

4 0

3 years ago