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katen-ka-za [31]
3 years ago
5

There are 90 apples shared equally among 6 baskets. Hun buys 1 basket of apples. He uses the apples to make 3 pies. Each pie has

the same number of apples in it. How many apples are in each pie? [Answer] apples
Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

To find the number of apples per basket we divide 90 by 6 to get 15. We know that he buys 15 apples. We now have to divide by 3 to get the number of apples per pie, because we know he used all 15 apples. The answer is 15/3 or 5 apples per pie. 5 apples

katrin2010 [14]3 years ago
6 0

Answers:   5

90÷6=15

15÷3=5

answer 5

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3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in
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Part A. We are given the following polynomial:

\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2

This is a polynomial of the form:

p=k(x-a)^b(x-c)^d\ldots(x-e)^f

The x-intercepts are the numbers that make the polynomial zero, that is:

\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}

The values of x are then found by setting each factor to zero:

\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}

Therefore, this values are:

\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}

In this case, the x-intercepts are:

\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.

6 0
1 year ago
Pls help it due ASAP. <br> Best get brainiest
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Assuming it is a Obtuse Scalene Triangle
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